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Java-based LeetCode algorithm problem solutions, regularly updated
91\. Decode Ways
Medium
A message containing letters from `A-Z` can be **encoded** into numbers using the following mapping:
'A' -> "1" 'B' -> "2" ... 'Z' -> "26"
To **decode** an encoded message, all the digits must be grouped then mapped back into letters using the reverse of the mapping above (there may be multiple ways). For example, `"11106"` can be mapped into:
* `"AAJF"` with the grouping `(1 1 10 6)`
* `"KJF"` with the grouping `(11 10 6)`
Note that the grouping `(1 11 06)` is invalid because `"06"` cannot be mapped into `'F'` since `"6"` is different from `"06"`.
Given a string `s` containing only digits, return _the **number** of ways to **decode** it_.
The answer is guaranteed to fit in a **32-bit** integer.
**Example 1:**
**Input:** s = "12"
**Output:** 2
**Explanation:** "12" could be decoded as "AB" (1 2) or "L" (12).
**Example 2:**
**Input:** s = "226"
**Output:** 3
**Explanation:** "226" could be decoded as "BZ" (2 26), "VF" (22 6), or "BBF" (2 2 6).
**Example 3:**
**Input:** s = "0"
**Output:** 0
**Explanation:** There is no character that is mapped to a number starting with 0. The only valid mappings with 0 are 'J' -> "10" and 'T' -> "20", neither of which start with 0. Hence, there are no valid ways to decode this since all digits need to be mapped.
**Example 4:**
**Input:** s = "06"
**Output:** 0
**Explanation:** "06" cannot be mapped to "F" because of the leading zero ("6" is different from "06").
**Constraints:**
* `1 <= s.length <= 100`
* `s` contains only digits and may contain leading zero(s).