g0101_0200.s0184_department_highest_salary.script.sql Maven / Gradle / Ivy

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Java-based LeetCode algorithm problem solutions, regularly updated

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# Write your MySQL query statement below
# #Medium #Database #2022_06_27_Time_590_ms_(73.49%)_Space_0B_(100.00%)
SELECT
    d.Name AS Department,
    Sel.Name AS Employee,
    Sel.Salary AS Salary
FROM
(
    SELECT
        Name,
        Salary,
        DepartmentId,
        DENSE_RANK() OVER (PARTITION BY DepartmentId ORDER BY Salary DESC) AS dr
    FROM Employee 
) AS Sel
INNER JOIN Department d ON d.Id = Sel.DepartmentId
WHERE Sel.dr = 1