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g0901_1000.s0908_smallest_range_i.readme.md Maven / Gradle / Ivy

908\. Smallest Range I

Easy

You are given an integer array `nums` and an integer `k`.

In one operation, you can choose any index `i` where `0 <= i < nums.length` and change `nums[i]` to `nums[i] + x` where `x` is an integer from the range `[-k, k]`. You can apply this operation **at most once** for each index `i`.

The **score** of `nums` is the difference between the maximum and minimum elements in `nums`.

Return _the minimum **score** of_ `nums` _after applying the mentioned operation at most once for each index in it_.

**Example 1:**

**Input:** nums = [1], k = 0

**Output:** 0

**Explanation:** The score is max(nums) - min(nums) = 1 - 1 = 0.

**Example 2:**

**Input:** nums = [0,10], k = 2

**Output:** 6

**Explanation:** Change nums to be [2, 8]. The score is max(nums) - min(nums) = 8 - 2 = 6.

**Example 3:**

**Input:** nums = [1,3,6], k = 3

**Output:** 0

**Explanation:** Change nums to be [4, 4, 4]. The score is max(nums) - min(nums) = 4 - 4 = 0.

**Constraints:**

*   1 <= nums.length <= 104
*   0 <= nums[i] <= 104
*   0 <= k <= 104