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Java-based LeetCode algorithm problem solutions, regularly updated
1179\. Reformat Department Table
Easy
SQL Schema
Table: `Department`
+-------------+---------+
| Column Name | Type |
+-------------+---------+
| id | int |
| revenue | int |
| month | varchar |
+-------------+---------+
(id, month) is the primary key of this table.
The table has information about the revenue of each department per month.
The month has values in ["Jan","Feb","Mar","Apr","May","Jun","Jul","Aug","Sep","Oct","Nov","Dec"].
Write an SQL query to reformat the table such that there is a department id column and a revenue column **for each month**.
Return the result table in **any order**.
The query result format is in the following example.
**Example 1:**
**Input:**
Department table:
+------+---------+-------+
| id | revenue | month |
+------+---------+-------+
| 1 | 8000 | Jan |
| 2 | 9000 | Jan |
| 3 | 10000 | Feb |
| 1 | 7000 | Feb |
| 1 | 6000 | Mar |
+------+---------+-------+
**Output:**
+------+-------------+-------------+-------------+-----+-------------+
| id | Jan_Revenue | Feb_Revenue | Mar_Revenue | ... | Dec_Revenue |
+------+-------------+-------------+-------------+-----+-------------+
| 1 | 8000 | 7000 | 6000 | ... | null |
| 2 | 9000 | null | null | ... | null |
| 3 | null | 10000 | null | ... | null |
+------+-------------+-------------+-------------+-----+-------------+
**Explanation:** The revenue from Apr to Dec is null.
Note that the result table has 13 columns (1 for the department id + 12 for the months).