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Java-based LeetCode algorithm problem solutions, regularly updated
1911\. Maximum Alternating Subsequence Sum
Medium
The **alternating sum** of a **0-indexed** array is defined as the **sum** of the elements at **even** indices **minus** the **sum** of the elements at **odd** indices.
* For example, the alternating sum of `[4,2,5,3]` is `(4 + 5) - (2 + 3) = 4`.
Given an array `nums`, return _the **maximum alternating sum** of any subsequence of_ `nums` _(after **reindexing** the elements of the subsequence)_.
A **subsequence** of an array is a new array generated from the original array by deleting some elements (possibly none) without changing the remaining elements' relative order. For example, `[2,7,4]` is a subsequence of `[4,2,3,7,2,1,4]` (the underlined elements), while `[2,4,2]` is not.
**Example 1:**
**Input:** nums = [4,2,5,3]
**Output:** 7
**Explanation:** It is optimal to choose the subsequence [4,2,5] with alternating sum (4 + 5) - 2 = 7.
**Example 2:**
**Input:** nums = [5,6,7,8]
**Output:** 8
**Explanation:** It is optimal to choose the subsequence [8] with alternating sum 8.
**Example 3:**
**Input:** nums = [6,2,1,2,4,5]
**Output:** 10
**Explanation:** It is optimal to choose the subsequence [6,1,5] with alternating sum (6 + 5) - 1 = 10.
**Constraints:**
* 1 <= nums.length <= 105
* 1 <= nums[i] <= 105