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Java-based LeetCode algorithm problem solutions, regularly updated
1914\. Cyclically Rotating a Grid
Medium
You are given an `m x n` integer matrix `grid`, where `m` and `n` are both **even** integers, and an integer `k`.
The matrix is composed of several layers, which is shown in the below image, where each color is its own layer:
![](https://assets.leetcode.com/uploads/2021/06/10/ringofgrid.png)
A cyclic rotation of the matrix is done by cyclically rotating **each layer** in the matrix. To cyclically rotate a layer once, each element in the layer will take the place of the adjacent element in the **counter-clockwise** direction. An example rotation is shown below:
![](https://assets.leetcode.com/uploads/2021/06/22/explanation_grid.jpg)
Return _the matrix after applying_ `k` _cyclic rotations to it_.
**Example 1:**
![](https://assets.leetcode.com/uploads/2021/06/19/rod2.png)
**Input:** grid = [[40,10],[30,20]], k = 1
**Output:** [[10,20],[40,30]]
**Explanation:** The figures above represent the grid at every state.
**Example 2:**
**![](https://assets.leetcode.com/uploads/2021/06/10/ringofgrid5.png)** **![](https://assets.leetcode.com/uploads/2021/06/10/ringofgrid6.png)** **![](https://assets.leetcode.com/uploads/2021/06/10/ringofgrid7.png)**
**Input:** grid = [[1,2,3,4],[5,6,7,8],[9,10,11,12],[13,14,15,16]], k = 2
**Output:** [[3,4,8,12],[2,11,10,16],[1,7,6,15],[5,9,13,14]]
**Explanation:** The figures above represent the grid at every state.
**Constraints:**
* `m == grid.length`
* `n == grid[i].length`
* `2 <= m, n <= 50`
* Both `m` and `n` are **even** integers.
* `1 <= grid[i][j] <= 5000`
* 1 <= k <= 109