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Java-based LeetCode algorithm problem solutions, regularly updated
2090\. K Radius Subarray Averages
Medium
You are given a **0-indexed** array `nums` of `n` integers, and an integer `k`.
The **k-radius average** for a subarray of `nums` **centered** at some index `i` with the **radius** `k` is the average of **all** elements in `nums` between the indices `i - k` and `i + k` (**inclusive**). If there are less than `k` elements before **or** after the index `i`, then the **k-radius average** is `-1`.
Build and return _an array_ `avgs` _of length_ `n` _where_ `avgs[i]` _is the **k-radius average** for the subarray centered at index_ `i`.
The **average** of `x` elements is the sum of the `x` elements divided by `x`, using **integer division**. The integer division truncates toward zero, which means losing its fractional part.
* For example, the average of four elements `2`, `3`, `1`, and `5` is `(2 + 3 + 1 + 5) / 4 = 11 / 4 = 2.75`, which truncates to `2`.
**Example 1:**
![](https://assets.leetcode.com/uploads/2021/11/07/eg1.png)
**Input:** nums = [7,4,3,9,1,8,5,2,6], k = 3
**Output:** [-1,-1,-1,5,4,4,-1,-1,-1]
**Explanation:**
- avg[0], avg[1], and avg[2] are -1 because there are less than k elements **before** each index.
- The sum of the subarray centered at index 3 with radius 3 is: 7 + 4 + 3 + 9 + 1 + 8 + 5 = 37.
Using **integer division**, avg[3] = 37 / 7 = 5.
- For the subarray centered at index 4, avg[4] = (4 + 3 + 9 + 1 + 8 + 5 + 2) / 7 = 4.
- For the subarray centered at index 5, avg[5] = (3 + 9 + 1 + 8 + 5 + 2 + 6) / 7 = 4.
- avg[6], avg[7], and avg[8] are -1 because there are less than k elements **after** each index.
**Example 2:**
**Input:** nums = [100000], k = 0
**Output:** [100000]
**Explanation:**
- The sum of the subarray centered at index 0 with radius 0 is: 100000.
avg[0] = 100000 / 1 = 100000.
**Example 3:**
**Input:** nums = [8], k = 100000
**Output:** [-1]
**Explanation:**
- avg[0] is -1 because there are less than k elements before and after index 0.
**Constraints:**
* `n == nums.length`
* 1 <= n <= 105
* 0 <= nums[i], k <= 105