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Java-based LeetCode algorithm problem solutions, regularly updated
2172\. Maximum AND Sum of Array
Hard
You are given an integer array `nums` of length `n` and an integer `numSlots` such that `2 * numSlots >= n`. There are `numSlots` slots numbered from `1` to `numSlots`.
You have to place all `n` integers into the slots such that each slot contains at **most** two numbers. The **AND sum** of a given placement is the sum of the **bitwise** `AND` of every number with its respective slot number.
* For example, the **AND sum** of placing the numbers `[1, 3]` into slot `1` and `[4, 6]` into slot `2` is equal to `(1 AND 1) + (3 AND 1) + (4 AND 2) + (6 AND 2) = 1 + 1 + 0 + 2 = 4`.
Return _the maximum possible **AND sum** of_ `nums` _given_ `numSlots` _slots._
**Example 1:**
**Input:** nums = [1,2,3,4,5,6], numSlots = 3
**Output:** 9
**Explanation:** One possible placement is [1, 4] into slot 1, [2, 6] into slot 2, and [3, 5] into slot 3.
This gives the maximum AND sum of (1 AND 1) + (4 AND 1) + (2 AND 2) + (6 AND 2) + (3 AND 3) + (5 AND 3) = 1 + 0 + 2 + 2 + 3 + 1 = 9.
**Example 2:**
**Input:** nums = [1,3,10,4,7,1], numSlots = 9
**Output:** 24
**Explanation:** One possible placement is [1, 1] into slot 1, [3] into slot 3, [4] into slot 4, [7] into slot 7, and [10] into slot 9.
This gives the maximum AND sum of (1 AND 1) + (1 AND 1) + (3 AND 3) + (4 AND 4) + (7 AND 7) + (10 AND 9) = 1 + 1 + 3 + 4 + 7 + 8 = 24.
Note that slots 2, 5, 6, and 8 are empty which is permitted.
**Constraints:**
* `n == nums.length`
* `1 <= numSlots <= 9`
* `1 <= n <= 2 * numSlots`
* `1 <= nums[i] <= 15`