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g2401_2500.s2402_meeting_rooms_iii.readme.md Maven / Gradle / Ivy

2402\. Meeting Rooms III

Hard

You are given an integer `n`. There are `n` rooms numbered from `0` to `n - 1`.

You are given a 2D integer array `meetings` where meetings[i] = [starti, endi] means that a meeting will be held during the **half-closed** time interval [starti, endi). All the values of starti are **unique**.

Meetings are allocated to rooms in the following manner:

1.  Each meeting will take place in the unused room with the **lowest** number.
2.  If there are no available rooms, the meeting will be delayed until a room becomes free. The delayed meeting should have the **same** duration as the original meeting.
3.  When a room becomes unused, meetings that have an earlier original **start** time should be given the room.

Return _the **number** of the room that held the most meetings._ If there are multiple rooms, return _the room with the **lowest** number._

A **half-closed interval** `[a, b)` is the interval between `a` and `b` **including** `a` and **not including** `b`.

**Example 1:**

**Input:** n = 2, meetings = [[0,10],[1,5],[2,7],[3,4]]

**Output:** 0

**Explanation:**

- At time 0, both rooms are not being used. The first meeting starts in room 0.

- At time 1, only room 1 is not being used. The second meeting starts in room 1.

- At time 2, both rooms are being used. The third meeting is delayed.

- At time 3, both rooms are being used. The fourth meeting is delayed.

- At time 5, the meeting in room 1 finishes. The third meeting starts in room 1 for the time period [5,10).

- At time 10, the meetings in both rooms finish. The fourth meeting starts in room 0 for the time period [10,11).

Both rooms 0 and 1 held 2 meetings, so we return 0. 

**Example 2:**

**Input:** n = 3, meetings = [[1,20],[2,10],[3,5],[4,9],[6,8]]

**Output:** 1

**Explanation:**

- At time 1, all three rooms are not being used. The first meeting starts in room 0.

- At time 2, rooms 1 and 2 are not being used. The second meeting starts in room 1.

- At time 3, only room 2 is not being used. The third meeting starts in room 2.

- At time 4, all three rooms are being used. The fourth meeting is delayed.

- At time 5, the meeting in room 2 finishes. The fourth meeting starts in room 2 for the time period [5,10).

- At time 6, all three rooms are being used. The fifth meeting is delayed.

- At time 10, the meetings in rooms 1 and 2 finish. The fifth meeting starts in room 1 for the time period [10,12).

Room 0 held 1 meeting while rooms 1 and 2 each held 2 meetings, so we return 1. 

**Constraints:**

*   `1 <= n <= 100`
*   1 <= meetings.length <= 105
*   `meetings[i].length == 2`
*   0 <= starti < endi <= 5 * 105
*   All the values of starti are **unique**.