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Java-based LeetCode algorithm problem solutions, regularly updated
850\. Rectangle Area II
Hard
You are given a 2D array of axis-aligned `rectangles`. Each rectangle[i] = [xi1, yi1, xi2, yi2]
denotes the ith
rectangle where (xi1, yi1)
are the coordinates of the **bottom-left corner**, and (xi2, yi2)
are the coordinates of the **top-right corner**.
Calculate the **total area** covered by all `rectangles` in the plane. Any area covered by two or more rectangles should only be counted **once**.
Return _the **total area**_. Since the answer may be too large, return it **modulo** 109 + 7
.
**Example 1:**
![](https://s3-lc-upload.s3.amazonaws.com/uploads/2018/06/06/rectangle_area_ii_pic.png)
**Input:** rectangles = [[0,0,2,2],[1,0,2,3],[1,0,3,1]]
**Output:** 6
**Explanation:** A total area of 6 is covered by all three rectangales, as illustrated in the picture.
From (1,1) to (2,2), the green and red rectangles overlap.
From (1,0) to (2,3), all three rectangles overlap.
**Example 2:**
**Input:** rectangles = [[0,0,1000000000,1000000000]]
**Output:** 49
**Explanation:** The answer is 1018 modulo (109 + 7), which is 49.
**Constraints:**
* `1 <= rectangles.length <= 200`
* `rectanges[i].length == 4`
* 0 <= xi1, yi1, xi2, yi2 <= 109