g1201_1300.s1278_palindrome_partitioning_iii.Solution Maven / Gradle / Ivy
Go to download
Show more of this group Show more artifacts with this name
Show all versions of leetcode-in-java Show documentation
Show all versions of leetcode-in-java Show documentation
Java-based LeetCode algorithm problem solutions, regularly updated
package g1201_1300.s1278_palindrome_partitioning_iii;
// #Hard #String #Dynamic_Programming #2022_03_12_Time_4_ms_(89.93%)_Space_42.6_MB_(30.60%)
import java.util.Arrays;
public class Solution {
public int palindromePartition(String s, int k) {
int n = s.length();
int[][] pal = new int[n + 1][n + 1];
fillPal(s, n, pal);
int[][] dp = new int[n + 1][k + 1];
for (int[] row : dp) {
Arrays.fill(row, -1);
}
return calculateMinCost(s, 0, n, k, pal, dp);
}
private int calculateMinCost(String s, int index, int n, int k, int[][] pal, int[][] dp) {
if (index == n) {
return n;
}
if (k == 1) {
return pal[index][n - 1];
}
if (dp[index][k] != -1) {
return dp[index][k];
}
int ans = Integer.MAX_VALUE;
for (int i = index; i < n; i++) {
ans = Math.min(ans, pal[index][i] + calculateMinCost(s, i + 1, n, k - 1, pal, dp));
}
dp[index][k] = ans;
return ans;
}
private void fillPal(String s, int n, int[][] pal) {
for (int gap = 0; gap < n; gap++) {
for (int i = 0, j = gap; j < n; i++, j++) {
if (gap == 0) {
pal[i][i] = 0;
} else if (gap == 1) {
if (s.charAt(i) == s.charAt(i + 1)) {
pal[i][i + 1] = 0;
} else {
pal[i][i + 1] = 1;
}
} else {
if (s.charAt(i) == s.charAt(j)) {
pal[i][j] = pal[i + 1][j - 1];
} else {
pal[i][j] = pal[i + 1][j - 1] + 1;
}
}
}
}
}
}