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Java-based LeetCode algorithm problem solutions, regularly updated
1402\. Reducing Dishes
Hard
A chef has collected data on the `satisfaction` level of his `n` dishes. Chef can cook any dish in 1 unit of time.
**Like-time coefficient** of a dish is defined as the time taken to cook that dish including previous dishes multiplied by its satisfaction level i.e. `time[i] * satisfaction[i]`.
Return _the maximum sum of **like-time coefficient** that the chef can obtain after dishes preparation_.
Dishes can be prepared in **any** order and the chef can discard some dishes to get this maximum value.
**Example 1:**
**Input:** satisfaction = [-1,-8,0,5,-9]
**Output:** 14
**Explanation:** After Removing the second and last dish, the maximum total **like-time coefficient** will be equal to (-1\*1 + 0\*2 + 5\*3 = 14). Each dish is prepared in one unit of time.
**Example 2:**
**Input:** satisfaction = [4,3,2]
**Output:** 20
**Explanation:** Dishes can be prepared in any order, (2\*1 + 3\*2 + 4\*3 = 20)
**Example 3:**
**Input:** satisfaction = [-1,-4,-5]
**Output:** 0
**Explanation:** People do not like the dishes. No dish is prepared.
**Constraints:**
* `n == satisfaction.length`
* `1 <= n <= 500`
* `-1000 <= satisfaction[i] <= 1000`