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Java-based LeetCode algorithm problem solutions, regularly updated
2079\. Watering Plants
Medium
You want to water `n` plants in your garden with a watering can. The plants are arranged in a row and are labeled from `0` to `n - 1` from left to right where the ith plant is located at `x = i`. There is a river at `x = -1` that you can refill your watering can at.
Each plant needs a specific amount of water. You will water the plants in the following way:
* Water the plants in order from left to right.
* After watering the current plant, if you do not have enough water to **completely** water the next plant, return to the river to fully refill the watering can.
* You **cannot** refill the watering can early.
You are initially at the river (i.e., `x = -1`). It takes **one step** to move **one unit** on the x-axis.
Given a **0-indexed** integer array `plants` of `n` integers, where `plants[i]` is the amount of water the ith plant needs, and an integer `capacity` representing the watering can capacity, return _the **number of steps** needed to water all the plants_.
**Example 1:**
**Input:** plants = [2,2,3,3], capacity = 5
**Output:** 14
**Explanation:** Start at the river with a full watering can:
- Walk to plant 0 (1 step) and water it. Watering can has 3 units of water.
- Walk to plant 1 (1 step) and water it. Watering can has 1 unit of water.
- Since you cannot completely water plant 2, walk back to the river to refill (2 steps).
- Walk to plant 2 (3 steps) and water it. Watering can has 2 units of water.
- Since you cannot completely water plant 3, walk back to the river to refill (3 steps).
- Walk to plant 3 (4 steps) and water it.
Steps needed = 1 + 1 + 2 + 3 + 3 + 4 = 14.
**Example 2:**
**Input:** plants = [1,1,1,4,2,3], capacity = 4
**Output:** 30
**Explanation:** Start at the river with a full watering can:
- Water plants 0, 1, and 2 (3 steps). Return to river (3 steps).
- Water plant 3 (4 steps). Return to river (4 steps).
- Water plant 4 (5 steps). Return to river (5 steps).
- Water plant 5 (6 steps).
Steps needed = 3 + 3 + 4 + 4 + 5 + 5 + 6 = 30.
**Example 3:**
**Input:** plants = [7,7,7,7,7,7,7], capacity = 8
**Output:** 49
**Explanation:** You have to refill before watering each plant.
Steps needed = 1 + 1 + 2 + 2 + 3 + 3 + 4 + 4 + 5 + 5 + 6 + 6 + 7 = 49.
**Constraints:**
* `n == plants.length`
* `1 <= n <= 1000`
* 1 <= plants[i] <= 106
* max(plants[i]) <= capacity <= 109