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g2601_2700.s2614_prime_in_diagonal.readme.md Maven / Gradle / Ivy

2614\. Prime In Diagonal

Easy

You are given a 0-indexed two-dimensional integer array `nums`.

Return _the largest **prime** number that lies on at least one of the **diagonals** of_ `nums`. In case, no prime is present on any of the diagonals, return _0._

Note that:

*   An integer is **prime** if it is greater than `1` and has no positive integer divisors other than `1` and itself.
*   An integer `val` is on one of the **diagonals** of `nums` if there exists an integer `i` for which `nums[i][i] = val` or an `i` for which `nums[i][nums.length - i - 1] = val`.

![](https://assets.leetcode.com/uploads/2023/03/06/screenshot-2023-03-06-at-45648-pm.png)

In the above diagram, one diagonal is **[1,5,9]** and another diagonal is **[3,5,7]**.

**Example 1:**

**Input:** nums = [[1,2,3],[5,6,7],[9,10,11]]

**Output:** 11

**Explanation:** The numbers 1, 3, 6, 9, and 11 are the only numbers present on at least one of the diagonals. Since 11 is the largest prime, we return 11.

**Example 2:**

**Input:** nums = [[1,2,3],[5,17,7],[9,11,10]]

**Output:** 17

**Explanation:** The numbers 1, 3, 9, 10, and 17 are all present on at least one of the diagonals. 17 is the largest prime, so we return 17.

**Constraints:**

*   `1 <= nums.length <= 300`
*   nums.length == numsi.length
*   1 <= nums[i][j] <= 4*106