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g2801_2900.s2864_maximum_odd_binary_number.readme.md Maven / Gradle / Ivy

2864\. Maximum Odd Binary Number

Easy

You are given a **binary** string `s` that contains at least one `'1'`.

You have to **rearrange** the bits in such a way that the resulting binary number is the **maximum odd binary number** that can be created from this combination.

Return _a string representing the maximum odd binary number that can be created from the given combination._

**Note** that the resulting string **can** have leading zeros.

**Example 1:**

**Input:** s = "010"

**Output:** "001"

**Explanation:** Because there is just one '1', it must be in the last position. So the answer is "001".

**Example 2:**

**Input:** s = "0101"

**Output:** "1001"

**Explanation:** One of the '1's must be in the last position. The maximum number that can be made with the remaining digits is "100". So the answer is "1001".

**Constraints:**

*   `1 <= s.length <= 100`
*   `s` consists only of `'0'` and `'1'`.
*   `s` contains at least one `'1'`.