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Java-based LeetCode algorithm problem solutions, regularly updated
package g0401_0500.s0457_circular_array_loop;
// #Medium #Array #Hash_Table #Two_Pointers
import java.util.HashMap;
import java.util.Map;
public class Solution {
public boolean circularArrayLoop(int[] arr) {
int n = arr.length;
Map map = new HashMap<>();
// arr[i]%n==0 (cycle)
for (int start = 0; start < n; start++) {
if (map.containsKey(start)) {
// check if already visited
continue;
}
int curr = start;
// Check if the current index is valid
while (isValidCycle(start, curr, arr)) {
// marking current index visited and set value as start of loop
map.put(curr, start);
// steps to jump;
int jump = arr[curr] % n;
// Jumping x steps backwards is same as jumping (n-x) steps forward
// going to next index;
curr = (curr + jump + n) % n;
if (map.containsKey(curr)) {
// value already processed
if (map.get(curr) == start) {
// If equal to start then we have found a loop
return true;
}
// Else we can break since this has already been visited hence we will get the
// same result as before
break;
}
}
}
return false;
}
private boolean isValidCycle(int start, int curr, int[] arr) {
return (arr[start] <= 0 || arr[curr] >= 0)
&& (arr[start] >= 0 || arr[curr] <= 0)
&& (arr[curr] % arr.length != 0);
}
}