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Java-based LeetCode algorithm problem solutions, regularly updated
523\. Continuous Subarray Sum
Medium
Given an integer array `nums` and an integer `k`, return `true` _if_ `nums` _has a continuous subarray of size **at least two** whose elements sum up to a multiple of_ `k`_, or_ `false` _otherwise_.
An integer `x` is a multiple of `k` if there exists an integer `n` such that `x = n * k`. `0` is **always** a multiple of `k`.
**Example 1:**
**Input:** nums = [23,2,4,6,7], k = 6
**Output:** true
**Explanation:** [2, 4] is a continuous subarray of size 2 whose elements sum up to 6.
**Example 2:**
**Input:** nums = [23,2,6,4,7], k = 6
**Output:** true
**Explanation:** [23, 2, 6, 4, 7] is an continuous subarray of size 5 whose elements sum up to 42. 42 is a multiple of 6 because 42 = 7 \* 6 and 7 is an integer.
**Example 3:**
**Input:** nums = [23,2,6,4,7], k = 13
**Output:** false
**Constraints:**
* 1 <= nums.length <= 105
* 0 <= nums[i] <= 109
* 0 <= sum(nums[i]) <= 231 - 1
* 1 <= k <= 231 - 1