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Java-based LeetCode algorithm problem solutions, regularly updated
957\. Prison Cells After N Days
Medium
There are `8` prison cells in a row and each cell is either occupied or vacant.
Each day, whether the cell is occupied or vacant changes according to the following rules:
* If a cell has two adjacent neighbors that are both occupied or both vacant, then the cell becomes occupied.
* Otherwise, it becomes vacant.
**Note** that because the prison is a row, the first and the last cells in the row can't have two adjacent neighbors.
You are given an integer array `cells` where `cells[i] == 1` if the ith
cell is occupied and `cells[i] == 0` if the ith
cell is vacant, and you are given an integer `n`.
Return the state of the prison after `n` days (i.e., `n` such changes described above).
**Example 1:**
**Input:** cells = [0,1,0,1,1,0,0,1], n = 7
**Output:** [0,0,1,1,0,0,0,0]
**Explanation:** The following table summarizes the state of the prison on each day:
Day 0: [0, 1, 0, 1, 1, 0, 0, 1]
Day 1: [0, 1, 1, 0, 0, 0, 0, 0]
Day 2: [0, 0, 0, 0, 1, 1, 1, 0]
Day 3: [0, 1, 1, 0, 0, 1, 0, 0]
Day 4: [0, 0, 0, 0, 0, 1, 0, 0]
Day 5: [0, 1, 1, 1, 0, 1, 0, 0]
Day 6: [0, 0, 1, 0, 1, 1, 0, 0]
Day 7: [0, 0, 1, 1, 0, 0, 0, 0]
**Example 2:**
**Input:** cells = [1,0,0,1,0,0,1,0], n = 1000000000
**Output:** [0,0,1,1,1,1,1,0]
**Constraints:**
* `cells.length == 8`
* `cells[i]` is either `0` or `1`.
* 1 <= n <= 109