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g3001_3100.s3033_modify_the_matrix.readme.md Maven / Gradle / Ivy

3033\. Modify the Matrix

Easy

Given a **0-indexed** `m x n` integer matrix `matrix`, create a new **0-indexed** matrix called `answer`. Make `answer` equal to `matrix`, then replace each element with the value `-1` with the **maximum** element in its respective column.

Return _the matrix_ `answer`.

**Example 1:**

![](https://assets.leetcode.com/uploads/2023/12/24/matrix1.png)

**Input:** matrix = [[1,2,-1],[4,-1,6],[7,8,9]]

**Output:** [[1,2,9],[4,8,6],[7,8,9]]

**Explanation:** The diagram above shows the elements that are changed (in blue). 
- We replace the value in the cell [1][1] with the maximum value in the column 1, that is 8. 
- We replace the value in the cell [0][2] with the maximum value in the column 2, that is 9.

**Example 2:**

![](https://assets.leetcode.com/uploads/2023/12/24/matrix2.png)

**Input:** matrix = [[3,-1],[5,2]]

**Output:** [[3,2],[5,2]]

**Explanation:** The diagram above shows the elements that are changed (in blue).

**Constraints:**

*   `m == matrix.length`
*   `n == matrix[i].length`
*   `2 <= m, n <= 50`
*   `-1 <= matrix[i][j] <= 100`
*   The input is generated such that each column contains at least one non-negative integer.