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The Apache Commons Codec package contains simple encoder and decoders for
various formats such as Base64 and Hexadecimal. In addition to these
widely used encoders and decoders, the codec package also maintains a
collection of phonetic encoding utilities.
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/* ====================================================================
Licensed to the Apache Software Foundation (ASF) under one or more
contributor license agreements. See the NOTICE file distributed with
this work for additional information regarding copyright ownership.
The ASF licenses this file to You under the Apache License, Version 2.0
(the "License"); you may not use this file except in compliance with
the License. You may obtain a copy of the License at
http://www.apache.org/licenses/LICENSE-2.0
Unless required by applicable law or agreed to in writing, software
distributed under the License is distributed on an "AS IS" BASIS,
WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
See the License for the specific language governing permissions and
limitations under the License.
==================================================================== */
package org.apache.poi.hssf.util;
/**
* Utility class for helping convert RK numbers.
*
* @see org.apache.poi.hssf.record.MulRKRecord
* @see org.apache.poi.hssf.record.RKRecord
*/
public final class RKUtil {
private RKUtil() {
// no instances of this class
}
/**
* Do the dirty work of decoding; made a private static method to
* facilitate testing the algorithm
*/
public static double decodeNumber(int number) {
long raw_number = number;
// mask off the two low-order bits, 'cause they're not part of
// the number
raw_number = raw_number >> 2;
double rvalue = 0;
if ((number & 0x02) == 0x02)
{
// ok, it's just a plain ol' int; we can handle this
// trivially by casting
rvalue = raw_number;
}
else
{
// also trivial, but not as obvious ... left shift the
// bits high and use that clever static method in Double
// to convert the resulting bit image to a double
rvalue = Double.longBitsToDouble(raw_number << 34);
}
if ((number & 0x01) == 0x01)
{
// low-order bit says divide by 100, and so we do. Why?
// 'cause that's what the algorithm says. Can't fight city
// hall, especially if it's the city of Redmond
rvalue /= 100;
}
return rvalue;
}
}