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Implementation of various string similarity and distance algorithms: Levenshtein, Jaro-winkler, n-Gram, Q-Gram, Jaccard index, Longest Common Subsequence edit distance, cosine similarity...
package info.debatty.java.stringsimilarity;
import info.debatty.java.stringsimilarity.interfaces.MetricStringDistance;
/**
* The Levenshtein distance between two words is the minimum number of
* single-character edits (insertions, deletions or substitutions) required to
* change one word into the other.
*
* @author Thibault Debatty
*/
public class Levenshtein implements MetricStringDistance {
public static void main (String[] args) {
Levenshtein l = new Levenshtein();
System.out.println(l.distance("My string", "My $tring"));
System.out.println(l.distance("My string", "M string2"));
System.out.println(l.distance("My string", "My $tring"));
}
/**
* The Levenshtein distance, or edit distance, between two words is the
* minimum number of single-character edits (insertions, deletions or
* substitutions) required to change one word into the other.
*
* http://en.wikipedia.org/wiki/Levenshtein_distance
*
* It is always at least the difference of the sizes of the two strings.
* It is at most the length of the longer string.
* It is zero if and only if the strings are equal.
* If the strings are the same size, the Hamming distance is an upper bound
* on the Levenshtein distance.
* The Levenshtein distance verifies the triangle inequality (the distance
* between two strings is no greater than the sum Levenshtein distances from
* a third string).
*
* Implementation uses dynamic programming (Wagner–Fischer algorithm), with
* only 2 rows of data. The space requirement is thus O(m) and the algorithm
* runs in O(mn).
*
* @param s1
* @param s2
* @return
*/
public double distance(String s1, String s2) {
if (s1.equals(s2)){
return 0;
}
if (s1.length() == 0) {
return s2.length();
}
if (s2.length() == 0) {
return s1.length();
}
// create two work vectors of integer distances
int[] v0 = new int[s2.length() + 1];
int[] v1 = new int[s2.length() + 1];
int[] vtemp;
// initialize v0 (the previous row of distances)
// this row is A[0][i]: edit distance for an empty s
// the distance is just the number of characters to delete from t
for (int i = 0; i < v0.length; i++) {
v0[i] = i;
}
for (int i = 0; i < s1.length(); i++) {
// calculate v1 (current row distances) from the previous row v0
// first element of v1 is A[i+1][0]
// edit distance is delete (i+1) chars from s to match empty t
v1[0] = i + 1;
// use formula to fill in the rest of the row
for (int j = 0; j < s2.length(); j++) {
int cost = (s1.charAt(i) == s2.charAt(j)) ? 0 : 1;
v1[j + 1] = Math.min(
v1[j] + 1, // Cost of insertion
Math.min(
v0[j + 1] + 1, // Cost of remove
v0[j] + cost)); // Cost of substitution
}
// copy v1 (current row) to v0 (previous row) for next iteration
//System.arraycopy(v1, 0, v0, 0, v0.length);
// Flip references to current and previous row
vtemp = v0;
v0 = v1;
v1 = vtemp;
}
return v0[s2.length()];
}
}