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// Protocol Buffers - Google's data interchange format
// Copyright 2008 Google Inc.  All rights reserved.
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package nl.topicus.jdbc.shaded.com.google.protobuf;

import java.io.ByteArrayInputStream;
import java.io.IOException;
import java.io.InputStream;
import java.io.InvalidObjectException;
import java.io.ObjectInputStream;
import java.io.OutputStream;
import java.nio.ByteBuffer;
import java.nio.charset.Charset;
import java.util.ArrayList;
import java.util.Arrays;
import java.util.Iterator;
import java.util.List;
import java.util.NoSuchElementException;
import java.util.Stack;

/**
 * Class to represent {@code ByteStrings} formed by concatenation of other
 * ByteStrings, without copying the data in the pieces. The concatenation is
 * represented as a tree whose leaf nodes are each a
 * {@link nl.topicus.jdbc.shaded.com.google.protobuf.ByteString.LeafByteString}.
 *
 * 

Most of the operation here is inspired by the now-famous paper * BAP95 Ropes: an Alternative to Strings hans-j. boehm, russ atkinson and * michael plass * *

The algorithms described in the paper have been implemented for character * strings in {@code nl.topicus.jdbc.shaded.com.google.common.string.Rope} and in the c++ class {@code * cord.cc}. * *

Fundamentally the Rope algorithm represents the collection of pieces as a * binary tree. BAP95 uses a Fibonacci bound relating depth to a minimum * sequence length, sequences that are too short relative to their depth cause a * tree rebalance. More precisely, a tree of depth d is "balanced" in the * terminology of BAP95 if its length is at least F(d+2), where F(n) is the * n-the Fibonacci number. Thus for depths 0, 1, 2, 3, 4, 5,... we have minimum * lengths 1, 2, 3, 5, 8, 13,... * * @author [email protected] (Carl Haverl) */ final class RopeByteString extends ByteString { /** * BAP95. Let Fn be the nth Fibonacci number. A {@link RopeByteString} of * depth n is "balanced", i.e flat enough, if its length is at least Fn+2, * e.g. a "balanced" {@link RopeByteString} of depth 1 must have length at * least 2, of depth 4 must have length >= 8, etc. * *

There's nothing special about using the Fibonacci numbers for this, but * they are a reasonable sequence for encapsulating the idea that we are OK * with longer strings being encoded in deeper binary trees. * *

For 32-bit integers, this array has length 46. */ private static final int[] minLengthByDepth; static { // Dynamically generate the list of Fibonacci numbers the first time this // class is accessed. List numbers = new ArrayList(); // we skip the first Fibonacci number (1). So instead of: 1 1 2 3 5 8 ... // we have: 1 2 3 5 8 ... int f1 = 1; int f2 = 1; // get all the values until we roll over. while (f2 > 0) { numbers.add(f2); int temp = f1 + f2; f1 = f2; f2 = temp; } // we include this here so that we can index this array to [x + 1] in the // loops below. numbers.add(Integer.MAX_VALUE); minLengthByDepth = new int[numbers.size()]; for (int i = 0; i < minLengthByDepth.length; i++) { // unbox all the values minLengthByDepth[i] = numbers.get(i); } } private final int totalLength; private final ByteString left; private final ByteString right; private final int leftLength; private final int treeDepth; /** * Create a new RopeByteString, which can be thought of as a new tree node, by * recording references to the two given strings. * * @param left string on the left of this node, should have {@code size() > * 0} * @param right string on the right of this node, should have {@code size() > * 0} */ private RopeByteString(ByteString left, ByteString right) { this.left = left; this.right = right; leftLength = left.size(); totalLength = leftLength + right.size(); treeDepth = Math.max(left.getTreeDepth(), right.getTreeDepth()) + 1; } /** * Concatenate the given strings while performing various optimizations to * slow the growth rate of tree depth and tree node count. The result is * either a {@link nl.topicus.jdbc.shaded.com.google.protobuf.ByteString.LeafByteString} or a * {@link RopeByteString} depending on which optimizations, if any, were * applied. * *

Small pieces of length less than {@link * ByteString#CONCATENATE_BY_COPY_SIZE} may be copied by value here, as in * BAP95. Large pieces are referenced without copy. * * @param left string on the left * @param right string on the right * @return concatenation representing the same sequence as the given strings */ static ByteString concatenate(ByteString left, ByteString right) { if (right.size() == 0) { return left; } if (left.size() == 0) { return right; } final int newLength = left.size() + right.size(); if (newLength < ByteString.CONCATENATE_BY_COPY_SIZE) { // Optimization from BAP95: For short (leaves in paper, but just short // here) total length, do a copy of data to a new leaf. return concatenateBytes(left, right); } if (left instanceof RopeByteString) { final RopeByteString leftRope = (RopeByteString) left; if (leftRope.right.size() + right.size() < CONCATENATE_BY_COPY_SIZE) { // Optimization from BAP95: As an optimization of the case where the // ByteString is constructed by repeated concatenate, recognize the case // where a short string is concatenated to a left-hand node whose // right-hand branch is short. In the paper this applies to leaves, but // we just look at the length here. This has the advantage of shedding // references to unneeded data when substrings have been taken. // // When we recognize this case, we do a copy of the data and create a // new parent node so that the depth of the result is the same as the // given left tree. ByteString newRight = concatenateBytes(leftRope.right, right); return new RopeByteString(leftRope.left, newRight); } if (leftRope.left.getTreeDepth() > leftRope.right.getTreeDepth() && leftRope.getTreeDepth() > right.getTreeDepth()) { // Typically for concatenate-built strings the left-side is deeper than // the right. This is our final attempt to concatenate without // increasing the tree depth. We'll redo the node on the RHS. This // is yet another optimization for building the string by repeatedly // concatenating on the right. ByteString newRight = new RopeByteString(leftRope.right, right); return new RopeByteString(leftRope.left, newRight); } } // Fine, we'll add a node and increase the tree depth--unless we rebalance ;^) int newDepth = Math.max(left.getTreeDepth(), right.getTreeDepth()) + 1; if (newLength >= minLengthByDepth[newDepth]) { // The tree is shallow enough, so don't rebalance return new RopeByteString(left, right); } return new Balancer().balance(left, right); } /** * Concatenates two strings by copying data values. This is called in a few * cases in order to reduce the growth of the number of tree nodes. * * @param left string on the left * @param right string on the right * @return string formed by copying data bytes */ private static ByteString concatenateBytes(ByteString left, ByteString right) { int leftSize = left.size(); int rightSize = right.size(); byte[] bytes = new byte[leftSize + rightSize]; left.copyTo(bytes, 0, 0, leftSize); right.copyTo(bytes, 0, leftSize, rightSize); return ByteString.wrap(bytes); // Constructor wraps bytes } /** * Create a new RopeByteString for testing only while bypassing all the * defenses of {@link #concatenate(ByteString, ByteString)}. This allows * testing trees of specific structure. We are also able to insert empty * leaves, though these are dis-allowed, so that we can make sure the * implementation can withstand their presence. * * @param left string on the left of this node * @param right string on the right of this node * @return an unsafe instance for testing only */ static RopeByteString newInstanceForTest(ByteString left, ByteString right) { return new RopeByteString(left, right); } /** * Gets the byte at the given index. * Throws {@link ArrayIndexOutOfBoundsException} for backwards-compatibility * reasons although it would more properly be {@link * IndexOutOfBoundsException}. * * @param index index of byte * @return the value * @throws ArrayIndexOutOfBoundsException {@code index} is < 0 or >= size */ @Override public byte byteAt(int index) { checkIndex(index, totalLength); // Find the relevant piece by recursive descent if (index < leftLength) { return left.byteAt(index); } return right.byteAt(index - leftLength); } @Override public int size() { return totalLength; } // ================================================================= // Pieces @Override protected int getTreeDepth() { return treeDepth; } /** * Determines if the tree is balanced according to BAP95, which means the tree * is flat-enough with respect to the bounds. Note that this definition of * balanced is one where sub-trees of balanced trees are not necessarily * balanced. * * @return true if the tree is balanced */ @Override protected boolean isBalanced() { return totalLength >= minLengthByDepth[treeDepth]; } /** * Takes a substring of this one. This involves recursive descent along the * left and right edges of the substring, and referencing any wholly contained * segments in between. Any leaf nodes entirely uninvolved in the substring * will not be referenced by the substring. * *

Substrings of {@code length < 2} should result in at most a single * recursive call chain, terminating at a leaf node. Thus the result will be a * {@link nl.topicus.jdbc.shaded.com.google.protobuf.ByteString.LeafByteString}. * * @param beginIndex start at this index * @param endIndex the last character is the one before this index * @return substring leaf node or tree */ @Override public ByteString substring(int beginIndex, int endIndex) { final int length = checkRange(beginIndex, endIndex, totalLength); if (length == 0) { // Empty substring return ByteString.EMPTY; } if (length == totalLength) { // The whole string return this; } // Proper substring if (endIndex <= leftLength) { // Substring on the left return left.substring(beginIndex, endIndex); } if (beginIndex >= leftLength) { // Substring on the right return right.substring(beginIndex - leftLength, endIndex - leftLength); } // Split substring ByteString leftSub = left.substring(beginIndex); ByteString rightSub = right.substring(0, endIndex - leftLength); // Intentionally not rebalancing, since in many cases these two // substrings will already be less deep than the top-level // RopeByteString we're taking a substring of. return new RopeByteString(leftSub, rightSub); } // ================================================================= // ByteString -> byte[] @Override protected void copyToInternal(byte[] target, int sourceOffset, int targetOffset, int numberToCopy) { if (sourceOffset + numberToCopy <= leftLength) { left.copyToInternal(target, sourceOffset, targetOffset, numberToCopy); } else if (sourceOffset >= leftLength) { right.copyToInternal(target, sourceOffset - leftLength, targetOffset, numberToCopy); } else { int leftLength = this.leftLength - sourceOffset; left.copyToInternal(target, sourceOffset, targetOffset, leftLength); right.copyToInternal(target, 0, targetOffset + leftLength, numberToCopy - leftLength); } } @Override public void copyTo(ByteBuffer target) { left.copyTo(target); right.copyTo(target); } @Override public ByteBuffer asReadOnlyByteBuffer() { ByteBuffer byteBuffer = ByteBuffer.wrap(toByteArray()); return byteBuffer.asReadOnlyBuffer(); } @Override public List asReadOnlyByteBufferList() { // Walk through the list of LeafByteString's that make up this // rope, and add each one as a read-only ByteBuffer. List result = new ArrayList(); PieceIterator pieces = new PieceIterator(this); while (pieces.hasNext()) { LeafByteString byteString = pieces.next(); result.add(byteString.asReadOnlyByteBuffer()); } return result; } @Override public void writeTo(OutputStream outputStream) throws IOException { left.writeTo(outputStream); right.writeTo(outputStream); } @Override void writeToInternal(OutputStream out, int sourceOffset, int numberToWrite) throws IOException { if (sourceOffset + numberToWrite <= leftLength) { left.writeToInternal(out, sourceOffset, numberToWrite); } else if (sourceOffset >= leftLength) { right.writeToInternal(out, sourceOffset - leftLength, numberToWrite); } else { int numberToWriteInLeft = leftLength - sourceOffset; left.writeToInternal(out, sourceOffset, numberToWriteInLeft); right.writeToInternal(out, 0, numberToWrite - numberToWriteInLeft); } } @Override void writeTo(ByteOutput output) throws IOException { left.writeTo(output); right.writeTo(output); } @Override protected String toStringInternal(Charset charset) { return new String(toByteArray(), charset); } // ================================================================= // UTF-8 decoding @Override public boolean isValidUtf8() { int leftPartial = left.partialIsValidUtf8(Utf8.COMPLETE, 0, leftLength); int state = right.partialIsValidUtf8(leftPartial, 0, right.size()); return state == Utf8.COMPLETE; } @Override protected int partialIsValidUtf8(int state, int offset, int length) { int toIndex = offset + length; if (toIndex <= leftLength) { return left.partialIsValidUtf8(state, offset, length); } else if (offset >= leftLength) { return right.partialIsValidUtf8(state, offset - leftLength, length); } else { int leftLength = this.leftLength - offset; int leftPartial = left.partialIsValidUtf8(state, offset, leftLength); return right.partialIsValidUtf8(leftPartial, 0, length - leftLength); } } // ================================================================= // equals() and hashCode() @Override public boolean equals(Object other) { if (other == this) { return true; } if (!(other instanceof ByteString)) { return false; } ByteString otherByteString = (ByteString) other; if (totalLength != otherByteString.size()) { return false; } if (totalLength == 0) { return true; } // You don't really want to be calling equals on long strings, but since // we cache the hashCode, we effectively cache inequality. We use the cached // hashCode if it's already computed. It's arguable we should compute the // hashCode here, and if we're going to be testing a bunch of byteStrings, // it might even make sense. int thisHash = peekCachedHashCode(); int thatHash = otherByteString.peekCachedHashCode(); if (thisHash != 0 && thatHash != 0 && thisHash != thatHash) { return false; } return equalsFragments(otherByteString); } /** * Determines if this string is equal to another of the same length by * iterating over the leaf nodes. On each step of the iteration, the * overlapping segments of the leaves are compared. * * @param other string of the same length as this one * @return true if the values of this string equals the value of the given * one */ private boolean equalsFragments(ByteString other) { int thisOffset = 0; Iterator thisIter = new PieceIterator(this); LeafByteString thisString = thisIter.next(); int thatOffset = 0; Iterator thatIter = new PieceIterator(other); LeafByteString thatString = thatIter.next(); int pos = 0; while (true) { int thisRemaining = thisString.size() - thisOffset; int thatRemaining = thatString.size() - thatOffset; int bytesToCompare = Math.min(thisRemaining, thatRemaining); // At least one of the offsets will be zero boolean stillEqual = (thisOffset == 0) ? thisString.equalsRange(thatString, thatOffset, bytesToCompare) : thatString.equalsRange(thisString, thisOffset, bytesToCompare); if (!stillEqual) { return false; } pos += bytesToCompare; if (pos >= totalLength) { if (pos == totalLength) { return true; } throw new IllegalStateException(); } // We always get to the end of at least one of the pieces if (bytesToCompare == thisRemaining) { // If reached end of this thisOffset = 0; thisString = thisIter.next(); } else { thisOffset += bytesToCompare; } if (bytesToCompare == thatRemaining) { // If reached end of that thatOffset = 0; thatString = thatIter.next(); } else { thatOffset += bytesToCompare; } } } @Override protected int partialHash(int h, int offset, int length) { int toIndex = offset + length; if (toIndex <= leftLength) { return left.partialHash(h, offset, length); } else if (offset >= leftLength) { return right.partialHash(h, offset - leftLength, length); } else { int leftLength = this.leftLength - offset; int leftPartial = left.partialHash(h, offset, leftLength); return right.partialHash(leftPartial, 0, length - leftLength); } } // ================================================================= // Input stream @Override public CodedInputStream newCodedInput() { return CodedInputStream.newInstance(new RopeInputStream()); } @Override public InputStream newInput() { return new RopeInputStream(); } /** * This class implements the balancing algorithm of BAP95. In the paper the * authors use an array to keep track of pieces, while here we use a stack. * The tree is balanced by traversing subtrees in left to right order, and the * stack always contains the part of the string we've traversed so far. * *

One surprising aspect of the algorithm is the result of balancing is not * necessarily balanced, though it is nearly balanced. For details, see * BAP95. */ private static class Balancer { // Stack containing the part of the string, starting from the left, that // we've already traversed. The final string should be the equivalent of // concatenating the strings on the stack from bottom to top. private final Stack prefixesStack = new Stack(); private ByteString balance(ByteString left, ByteString right) { doBalance(left); doBalance(right); // Sweep stack to gather the result ByteString partialString = prefixesStack.pop(); while (!prefixesStack.isEmpty()) { ByteString newLeft = prefixesStack.pop(); partialString = new RopeByteString(newLeft, partialString); } // We should end up with a RopeByteString since at a minimum we will // create one from concatenating left and right return partialString; } private void doBalance(ByteString root) { // BAP95: Insert balanced subtrees whole. This means the result might not // be balanced, leading to repeated rebalancings on concatenate. However, // these rebalancings are shallow due to ignoring balanced subtrees, and // relatively few calls to insert() result. if (root.isBalanced()) { insert(root); } else if (root instanceof RopeByteString) { RopeByteString rbs = (RopeByteString) root; doBalance(rbs.left); doBalance(rbs.right); } else { throw new IllegalArgumentException( "Has a new type of ByteString been created? Found " + root.getClass()); } } /** * Push a string on the balance stack (BAP95). BAP95 uses an array and * calls the elements in the array 'bins'. We instead use a stack, so the * 'bins' of lengths are represented by differences between the elements of * minLengthByDepth. * *

If the length bin for our string, and all shorter length bins, are * empty, we just push it on the stack. Otherwise, we need to start * concatenating, putting the given string in the "middle" and continuing * until we land in an empty length bin that matches the length of our * concatenation. * * @param byteString string to place on the balance stack */ private void insert(ByteString byteString) { int depthBin = getDepthBinForLength(byteString.size()); int binEnd = minLengthByDepth[depthBin + 1]; // BAP95: Concatenate all trees occupying bins representing the length of // our new piece or of shorter pieces, to the extent that is possible. // The goal is to clear the bin which our piece belongs in, but that may // not be entirely possible if there aren't enough longer bins occupied. if (prefixesStack.isEmpty() || prefixesStack.peek().size() >= binEnd) { prefixesStack.push(byteString); } else { int binStart = minLengthByDepth[depthBin]; // Concatenate the subtrees of shorter length ByteString newTree = prefixesStack.pop(); while (!prefixesStack.isEmpty() && prefixesStack.peek().size() < binStart) { ByteString left = prefixesStack.pop(); newTree = new RopeByteString(left, newTree); } // Concatenate the given string newTree = new RopeByteString(newTree, byteString); // Continue concatenating until we land in an empty bin while (!prefixesStack.isEmpty()) { depthBin = getDepthBinForLength(newTree.size()); binEnd = minLengthByDepth[depthBin + 1]; if (prefixesStack.peek().size() < binEnd) { ByteString left = prefixesStack.pop(); newTree = new RopeByteString(left, newTree); } else { break; } } prefixesStack.push(newTree); } } private int getDepthBinForLength(int length) { int depth = Arrays.binarySearch(minLengthByDepth, length); if (depth < 0) { // It wasn't an exact match, so convert to the index of the containing // fragment, which is one less even than the insertion point. int insertionPoint = -(depth + 1); depth = insertionPoint - 1; } return depth; } } /** * This class is a continuable tree traversal, which keeps the state * information which would exist on the stack in a recursive traversal instead * on a stack of "Bread Crumbs". The maximum depth of the stack in this * iterator is the same as the depth of the tree being traversed. * *

This iterator is used to implement * {@link RopeByteString#equalsFragments(ByteString)}. */ private static class PieceIterator implements Iterator { private final Stack breadCrumbs = new Stack(); private LeafByteString next; private PieceIterator(ByteString root) { next = getLeafByLeft(root); } private LeafByteString getLeafByLeft(ByteString root) { ByteString pos = root; while (pos instanceof RopeByteString) { RopeByteString rbs = (RopeByteString) pos; breadCrumbs.push(rbs); pos = rbs.left; } return (LeafByteString) pos; } private LeafByteString getNextNonEmptyLeaf() { while (true) { // Almost always, we go through this loop exactly once. However, if // we discover an empty string in the rope, we toss it and try again. if (breadCrumbs.isEmpty()) { return null; } else { LeafByteString result = getLeafByLeft(breadCrumbs.pop().right); if (!result.isEmpty()) { return result; } } } } @Override public boolean hasNext() { return next != null; } /** * Returns the next item and advances one * {@link nl.topicus.jdbc.shaded.com.google.protobuf.ByteString.LeafByteString}. * * @return next non-empty LeafByteString or {@code null} */ @Override public LeafByteString next() { if (next == null) { throw new NoSuchElementException(); } LeafByteString result = next; next = getNextNonEmptyLeaf(); return result; } @Override public void remove() { throw new UnsupportedOperationException(); } } // ================================================================= // Serializable private static final long serialVersionUID = 1L; Object writeReplace() { return ByteString.wrap(toByteArray()); } private void readObject(@SuppressWarnings("unused") ObjectInputStream in) throws IOException { throw new InvalidObjectException( "RopeByteStream instances are not to be serialized directly"); } /** * This class is the {@link RopeByteString} equivalent for * {@link ByteArrayInputStream}. */ private class RopeInputStream extends InputStream { // Iterates through the pieces of the rope private PieceIterator pieceIterator; // The current piece private LeafByteString currentPiece; // The size of the current piece private int currentPieceSize; // The index of the next byte to read in the current piece private int currentPieceIndex; // The offset of the start of the current piece in the rope byte string private int currentPieceOffsetInRope; // Offset in the buffer at which user called mark(); private int mark; public RopeInputStream() { initialize(); } @Override public int read(byte b[], int offset, int length) { if (b == null) { throw new NullPointerException(); } else if (offset < 0 || length < 0 || length > b.length - offset) { throw new IndexOutOfBoundsException(); } return readSkipInternal(b, offset, length); } @Override public long skip(long length) { if (length < 0) { throw new IndexOutOfBoundsException(); } else if (length > Integer.MAX_VALUE) { length = Integer.MAX_VALUE; } return readSkipInternal(null, 0, (int) length); } /** * Internal implementation of read and skip. If b != null, then read the * next {@code length} bytes into the buffer {@code b} at * offset {@code offset}. If b == null, then skip the next {@code length} * bytes. *

* This method assumes that all error checking has already happened. *

* Returns the actual number of bytes read or skipped. */ private int readSkipInternal(byte b[], int offset, int length) { int bytesRemaining = length; while (bytesRemaining > 0) { advanceIfCurrentPieceFullyRead(); if (currentPiece == null) { if (bytesRemaining == length) { // We didn't manage to read anything return -1; } break; } else { // Copy the bytes from this piece. int currentPieceRemaining = currentPieceSize - currentPieceIndex; int count = Math.min(currentPieceRemaining, bytesRemaining); if (b != null) { currentPiece.copyTo(b, currentPieceIndex, offset, count); offset += count; } currentPieceIndex += count; bytesRemaining -= count; } } // Return the number of bytes read. return length - bytesRemaining; } @Override public int read() throws IOException { advanceIfCurrentPieceFullyRead(); if (currentPiece == null) { return -1; } else { return currentPiece.byteAt(currentPieceIndex++) & 0xFF; } } @Override public int available() throws IOException { int bytesRead = currentPieceOffsetInRope + currentPieceIndex; return RopeByteString.this.size() - bytesRead; } @Override public boolean markSupported() { return true; } @Override public void mark(int readAheadLimit) { // Set the mark to our position in the byte string mark = currentPieceOffsetInRope + currentPieceIndex; } @Override public synchronized void reset() { // Just reinitialize and skip the specified number of bytes. initialize(); readSkipInternal(null, 0, mark); } /** Common initialization code used by both the constructor and reset() */ private void initialize() { pieceIterator = new PieceIterator(RopeByteString.this); currentPiece = pieceIterator.next(); currentPieceSize = currentPiece.size(); currentPieceIndex = 0; currentPieceOffsetInRope = 0; } /** * Skips to the next piece if we have read all the data in the current * piece. Sets currentPiece to null if we have reached the end of the * input. */ private void advanceIfCurrentPieceFullyRead() { if (currentPiece != null && currentPieceIndex == currentPieceSize) { // Generally, we can only go through this loop at most once, since // empty strings can't end up in a rope. But better to test. currentPieceOffsetInRope += currentPieceSize; currentPieceIndex = 0; if (pieceIterator.hasNext()) { currentPiece = pieceIterator.next(); currentPieceSize = currentPiece.size(); } else { currentPiece = null; currentPieceSize = 0; } } } } }





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