org.evosuite.continuous.job.schedule.BudgetSchedule Maven / Gradle / Ivy
/**
* Copyright (C) 2010-2017 Gordon Fraser, Andrea Arcuri and EvoSuite
* contributors
*
* This file is part of EvoSuite.
*
* EvoSuite is free software: you can redistribute it and/or modify it
* under the terms of the GNU Lesser General Public License as published
* by the Free Software Foundation, either version 3.0 of the License, or
* (at your option) any later version.
*
* EvoSuite is distributed in the hope that it will be useful, but
* WITHOUT ANY WARRANTY; without even the implied warranty of
* MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the GNU
* Lesser Public License for more details.
*
* You should have received a copy of the GNU Lesser General Public
* License along with EvoSuite. If not, see .
*/
package org.evosuite.continuous.job.schedule;
import java.util.Collections;
import java.util.Comparator;
import java.util.LinkedList;
import java.util.List;
import org.evosuite.continuous.job.JobDefinition;
import org.evosuite.continuous.job.JobScheduler;
import org.evosuite.continuous.project.ProjectStaticData;
import org.evosuite.continuous.project.ProjectStaticData.ClassInfo;
/**
* CUTs with more branches will be given more time (ie search budget)
*
* @author arcuri
*
*/
public class BudgetSchedule extends OneTimeSchedule{
public BudgetSchedule(JobScheduler scheduler) {
super(scheduler);
}
@Override
protected List createScheduleOnce() {
ProjectStaticData data = scheduler.getProjectData();
if(data.getTotalNumberOfBranches() == 0){
return new SimpleSchedule(scheduler).createScheduleOnce();
}
int maximumBudgetPerCore = 60 * scheduler.getConfiguration().timeInMinutes;
/*
* the total budget we need to choose how to allocate
*/
int totalBudget = maximumBudgetPerCore * scheduler.getConfiguration().getNumberOfUsableCores();
/*
* a part of the budget is fixed, as each CUT needs a minimum
* of it.
*/
int minTime = 60 * scheduler.getConfiguration().minMinutesPerJob * data.getTotalNumberOfTestableCUTs();
/*
* this is what left from the minimum allocation, and that now we can
* choose how best to allocate
*/
int extraTime = totalBudget - minTime;
/*
* check how much time we can give extra for each branch in a CUT
*/
double timePerBranch = (double)extraTime / (double)data.getTotalNumberOfBranches();
int totalLeftOver = 0;
List jobs = new LinkedList<>();
for(ClassInfo info : data.getClassInfos()){
if(!info.isTestable()){
continue;
}
/*
* there is a minimum that is equal to all jobs,
* plus extra time based on number of branches
*/
int budget = 60 * scheduler.getConfiguration().minMinutesPerJob +
(int)(timePerBranch * info.numberOfBranches);
if(budget > maximumBudgetPerCore){
/*
* Need to guarantee that no job has more than
* maximumBudgetPerCore regardless of number of cores
*/
totalLeftOver += (budget - maximumBudgetPerCore);
budget = maximumBudgetPerCore;
}
JobDefinition job = new JobDefinition(
budget, scheduler.getConfiguration().getConstantMemoryPerJob(), info.getClassName(), 0, null, null);
jobs.add(job);
}
if(totalLeftOver > 0){
/*
* we still have some more budget to allocate
*/
distributeExtraBudgetEvenly(jobs,totalLeftOver,maximumBudgetPerCore);
}
/*
* using scheduling theory, there could be different
* best orders to maximize CPU usage.
* Here, at least for the time being, for simplicity
* we just try to execute the most expensive jobs
* as soon as possible
*/
Collections.sort(jobs, (a, b) -> {
/*
* the job with takes most time will be "lower".
* recall that sorting is in ascending order
*/
return b.seconds - a.seconds;
});
return jobs;
}
}