.kotlin.kotlin-compiler.1.3.11.source-code.ScriptRuntime Maven / Gradle / Ivy
/* -*- Mode: java; tab-width: 8; indent-tabs-mode: nil; c-basic-offset: 4 -*-
*
* The contents of this file are subject to the Netscape Public
* License Version 1.1 (the "License"); you may not use this file
* except in compliance with the License. You may obtain a copy of
* the License at http://www.mozilla.org/NPL/
*
* Software distributed under the License is distributed on an "AS
* IS" basis, WITHOUT WARRANTY OF ANY KIND, either express or
* implied. See the License for the specific language governing
* rights and limitations under the License.
*
* The Original Code is Rhino code, released
* May 6, 1999.
*
* The Initial Developer of the Original Code is Netscape
* Communications Corporation. Portions created by Netscape are
* Copyright (C) 1997-2000 Netscape Communications Corporation. All
* Rights Reserved.
*
* Contributor(s):
* Patrick Beard
* Norris Boyd
* Igor Bukanov
* Roger Lawrence
* Frank Mitchell
* Andrew Wason
*
* Alternatively, the contents of this file may be used under the
* terms of the GNU Public License (the "GPL"), in which case the
* provisions of the GPL are applicable instead of those above.
* If you wish to allow use of your version of this file only
* under the terms of the GPL and not to allow others to use your
* version of this file under the NPL, indicate your decision by
* deleting the provisions above and replace them with the notice
* and other provisions required by the GPL. If you do not delete
* the provisions above, a recipient may use your version of this
* file under either the NPL or the GPL.
*/
// Modified by Google
package com.google.gwt.dev.js.rhino;
/**
* This is the class that implements the runtime.
*/
public class ScriptRuntime {
public static double NaN = 0.0d / 0.0;
/*
* Helper function for toNumber, parseInt, and TokenStream.getToken.
*/
static double stringToNumber(String s, int start, int radix) {
char digitMax = '9';
char lowerCaseBound = 'a';
char upperCaseBound = 'A';
int len = s.length();
if (radix < 10) {
digitMax = (char) ('0' + radix - 1);
}
if (radix > 10) {
lowerCaseBound = (char) ('a' + radix - 10);
upperCaseBound = (char) ('A' + radix - 10);
}
int end;
double sum = 0.0;
for (end=start; end < len; end++) {
char c = s.charAt(end);
int newDigit;
if ('0' <= c && c <= digitMax)
newDigit = c - '0';
else if ('a' <= c && c < lowerCaseBound)
newDigit = c - 'a' + 10;
else if ('A' <= c && c < upperCaseBound)
newDigit = c - 'A' + 10;
else
break;
sum = sum*radix + newDigit;
}
if (start == end) {
return NaN;
}
if (sum >= 9007199254740992.0) {
if (radix == 10) {
/* If we're accumulating a decimal number and the number
* is >= 2^53, then the result from the repeated multiply-add
* above may be inaccurate. Call Java to get the correct
* answer.
*/
try {
return Double.valueOf(s.substring(start, end)).doubleValue();
} catch (NumberFormatException nfe) {
return NaN;
}
} else if (radix == 2 || radix == 4 || radix == 8 ||
radix == 16 || radix == 32)
{
/* The number may also be inaccurate for one of these bases.
* This happens if the addition in value*radix + digit causes
* a round-down to an even least significant mantissa bit
* when the first dropped bit is a one. If any of the
* following digits in the number (which haven't been added
* in yet) are nonzero then the correct action would have
* been to round up instead of down. An example of this
* occurs when reading the number 0x1000000000000081, which
* rounds to 0x1000000000000000 instead of 0x1000000000000100.
*/
BinaryDigitReader bdr = new BinaryDigitReader(radix, s, start, end);
int bit;
sum = 0.0;
/* Skip leading zeros. */
do {
bit = bdr.getNextBinaryDigit();
} while (bit == 0);
if (bit == 1) {
/* Gather the 53 significant bits (including the leading 1) */
sum = 1.0;
for (int j = 52; j != 0; j--) {
bit = bdr.getNextBinaryDigit();
if (bit < 0)
return sum;
sum = sum*2 + bit;
}
/* bit54 is the 54th bit (the first dropped from the mantissa) */
int bit54 = bdr.getNextBinaryDigit();
if (bit54 >= 0) {
double factor = 2.0;
int sticky = 0; /* sticky is 1 if any bit beyond the 54th is 1 */
int bit3;
while ((bit3 = bdr.getNextBinaryDigit()) >= 0) {
sticky |= bit3;
factor *= 2;
}
sum += bit54 & (bit | sticky);
sum *= factor;
}
}
}
/* We don't worry about inaccurate numbers for any other base. */
}
return sum;
}
}