commonMain.aws.sdk.kotlin.services.bedrockagent.serde.ActionGroupExecutorDocumentSerializer.kt Maven / Gradle / Ivy

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The AWS SDK for Kotlin client for Bedrock Agent

There is a newer version: 1.3.77

// Code generated by smithy-kotlin-codegen. DO NOT EDIT!

package aws.sdk.kotlin.services.bedrockagent.serde

import aws.sdk.kotlin.services.bedrockagent.model.ActionGroupExecutor
import aws.smithy.kotlin.runtime.serde.SdkFieldDescriptor
import aws.smithy.kotlin.runtime.serde.SdkObjectDescriptor
import aws.smithy.kotlin.runtime.serde.SerialKind
import aws.smithy.kotlin.runtime.serde.SerializationException
import aws.smithy.kotlin.runtime.serde.Serializer
import aws.smithy.kotlin.runtime.serde.asSdkSerializable
import aws.smithy.kotlin.runtime.serde.deserializeList
import aws.smithy.kotlin.runtime.serde.deserializeMap
import aws.smithy.kotlin.runtime.serde.deserializeStruct
import aws.smithy.kotlin.runtime.serde.field
import aws.smithy.kotlin.runtime.serde.json.JsonDeserializer
import aws.smithy.kotlin.runtime.serde.json.JsonSerialName
import aws.smithy.kotlin.runtime.serde.serializeList
import aws.smithy.kotlin.runtime.serde.serializeMap
import aws.smithy.kotlin.runtime.serde.serializeStruct

internal fun serializeActionGroupExecutorDocument(serializer: Serializer, input: ActionGroupExecutor) {
    val CUSTOMCONTROL_DESCRIPTOR = SdkFieldDescriptor(SerialKind.Enum, JsonSerialName("customControl"))
    val LAMBDA_DESCRIPTOR = SdkFieldDescriptor(SerialKind.String, JsonSerialName("lambda"))
    val OBJ_DESCRIPTOR = SdkObjectDescriptor.build {
        field(CUSTOMCONTROL_DESCRIPTOR)
        field(LAMBDA_DESCRIPTOR)
    }

    serializer.serializeStruct(OBJ_DESCRIPTOR) {
        when (input) {
            is ActionGroupExecutor.Lambda -> field(LAMBDA_DESCRIPTOR, input.value)
            is ActionGroupExecutor.CustomControl -> field(CUSTOMCONTROL_DESCRIPTOR, input.value.value)
            is ActionGroupExecutor.SdkUnknown -> throw SerializationException("Cannot serialize SdkUnknown")
        }
    }
}