
cc.redberry.core.utils.MathUtils Maven / Gradle / Ivy
Go to download
Show more of this group Show more artifacts with this name
Show all versions of core Show documentation
Show all versions of core Show documentation
Redberry is an open source computer algebra system designed for tensor
manipulation. It implements basic computer algebra system routines as well as
complex tools for real computations in physics.
This is Redberry core, which contains the implementation of the basic
computer algebra routines and general-purpose transformations.
/*
* Redberry: symbolic tensor computations.
*
* Copyright (c) 2010-2014:
* Stanislav Poslavsky
* Bolotin Dmitriy
*
* This file is part of Redberry.
*
* Redberry is free software: you can redistribute it and/or modify
* it under the terms of the GNU General Public License as published by
* the Free Software Foundation, either version 3 of the License, or
* (at your option) any later version.
*
* Redberry is distributed in the hope that it will be useful,
* but WITHOUT ANY WARRANTY; without even the implied warranty of
* MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
* GNU General Public License for more details.
*
* You should have received a copy of the GNU General Public License
* along with Redberry. If not, see .
*/
package cc.redberry.core.utils;
import java.util.Arrays;
public final class MathUtils {
private MathUtils() {
}
/**
* Sort array & return array with removed repetitive values.
*
* @param values input array (this method will quickSort this array)
*
* @return sorted array of distinct values
*/
public static int[] getSortedDistinct(int[] values) {
if (values.length == 0)
return values;
Arrays.sort(values);
int shift = 0;
int i = 0;
while (i + shift + 1 < values.length)
if (values[i + shift] == values[i + shift + 1])
++shift;
else {
values[i] = values[i + shift];
++i;
}
values[i] = values[i + shift];
return Arrays.copyOf(values, i + 1);
}
/**
* Return the set difference B - A for int sets A and B.
Sets A and B
* must be represented as two sorted int arrays.
Repetitive values in A
* or B not allowed.
*
* @param a sorted array of distinct values. (set A)
* @param b sorted array of distinct values. (set B)
*
* @return the set of elements in B but not in A
*/
public static int[] intSetDifference(int[] a, int[] b) {
int bPointer = 0, aPointer = 0;
int counter = 0;
while (aPointer < a.length && bPointer < b.length)
if (a[aPointer] == b[bPointer]) {
aPointer++;
bPointer++;
} else if (a[aPointer] < b[bPointer])
aPointer++;
else if (a[aPointer] > b[bPointer]) {
counter++;
bPointer++;
}
counter += b.length - bPointer;
int[] result = new int[counter];
counter = 0;
aPointer = 0;
bPointer = 0;
while (aPointer < a.length && bPointer < b.length)
if (a[aPointer] == b[bPointer]) {
aPointer++;
bPointer++;
} else if (a[aPointer] < b[bPointer])
aPointer++;
else if (a[aPointer] > b[bPointer])
result[counter++] = b[bPointer++];
System.arraycopy(b, bPointer, result, counter, b.length - bPointer);
return result;
}
/**
* Return the union B + A for integer sets A and B.
Sets A and B must
* be represented as two sorted integer arrays.
Repetitive values in A
* or B not allowed.
*
* @param a sorted array of distinct values. (set A)
* @param b sorted array of distinct values. (set B)
*
* @return the set of elements from B and from A
*/
public static int[] intSetUnion(int[] a, int[] b) {
int bPointer = 0, aPointer = 0;
int counter = 0;
while (aPointer < a.length && bPointer < b.length)
if (a[aPointer] == b[bPointer]) {
aPointer++;
bPointer++;
counter++;
} else if (a[aPointer] < b[bPointer]) {
aPointer++;
counter++;
} else if (a[aPointer] > b[bPointer]) {
counter++;
bPointer++;
}
counter += (a.length - aPointer) + (b.length - bPointer); //Assert aPoiner==a.length || bPointer==b.length
int[] result = new int[counter];
counter = 0;
aPointer = 0;
bPointer = 0;
while (aPointer < a.length && bPointer < b.length)
if (a[aPointer] == b[bPointer]) {
result[counter++] = b[bPointer];
aPointer++;
bPointer++;
} else if (a[aPointer] < b[bPointer])
result[counter++] = a[aPointer++];
else if (a[aPointer] > b[bPointer])
result[counter++] = b[bPointer++];
if (aPointer == a.length)
System.arraycopy(b, bPointer, result, counter, b.length - bPointer);
else
System.arraycopy(a, aPointer, result, counter, a.length - aPointer);
return result;
}
}
© 2015 - 2025 Weber Informatics LLC | Privacy Policy