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Hutool是一个小而全的Java工具类库,通过静态方法封装,降低相关API的学习成本,提高工作效率,使Java拥有函数式语言般的优雅,让Java语言也可以“甜甜的”。
package cn.hutool.core.codec;
import cn.hutool.core.lang.Assert;
/**
* BCD码(Binary-Coded Decimal)亦称二进码十进数或二-十进制代码
* BCD码这种编码形式利用了四个位元来储存一个十进制的数码,使二进制和十进制之间的转换得以快捷的进行
* see http://cuisuqiang.iteye.com/blog/1429956
* @author Looly
*
* @deprecated 由于对于ASCII的编码解码有缺陷,且这种BCD实现并不规范,因此会在6.0.0中移除
*/
@Deprecated
public class BCD {
/**
* 字符串转BCD码
* @param asc ASCII字符串
* @return BCD
*/
public static byte[] strToBcd(String asc) {
Assert.notNull(asc, "ASCII must not be null!");
int len = asc.length();
int mod = len % 2;
if (mod != 0) {
asc = "0" + asc;
len = asc.length();
}
byte[] abt;
if (len >= 2) {
len >>= 1;
}
byte[] bbt;
bbt = new byte[len];
abt = asc.getBytes();
int j;
int k;
for (int p = 0; p < asc.length() / 2; p++) {
if ((abt[2 * p] >= '0') && (abt[2 * p] <= '9')) {
j = abt[2 * p] - '0';
} else if ((abt[2 * p] >= 'a') && (abt[2 * p] <= 'z')) {
j = abt[2 * p] - 'a' + 0x0a;
} else {
j = abt[2 * p] - 'A' + 0x0a;
}
if ((abt[2 * p + 1] >= '0') && (abt[2 * p + 1] <= '9')) {
k = abt[2 * p + 1] - '0';
} else if ((abt[2 * p + 1] >= 'a') && (abt[2 * p + 1] <= 'z')) {
k = abt[2 * p + 1] - 'a' + 0x0a;
} else {
k = abt[2 * p + 1] - 'A' + 0x0a;
}
int a = (j << 4) + k;
byte b = (byte) a;
bbt[p] = b;
}
return bbt;
}
/**
* ASCII转BCD
* @param ascii ASCII byte数组
* @return BCD
*/
public static byte[] ascToBcd(byte[] ascii) {
Assert.notNull(ascii, "Ascii must be not null!");
return ascToBcd(ascii, ascii.length);
}
/**
* ASCII转BCD
* @param ascii ASCII byte数组
* @param ascLength 长度
* @return BCD
*/
public static byte[] ascToBcd(byte[] ascii, int ascLength) {
Assert.notNull(ascii, "Ascii must be not null!");
byte[] bcd = new byte[ascLength / 2];
int j = 0;
for (int i = 0; i < (ascLength + 1) / 2; i++) {
bcd[i] = ascToBcd(ascii[j++]);
bcd[i] = (byte) (((j >= ascLength) ? 0x00 : ascToBcd(ascii[j++])) + (bcd[i] << 4));
}
return bcd;
}
/**
* BCD转ASCII字符串
* @param bytes BCD byte数组
* @return ASCII字符串
*/
public static String bcdToStr(byte[] bytes) {
Assert.notNull(bytes, "Bcd bytes must be not null!");
char[] temp = new char[bytes.length * 2];
char val;
for (int i = 0; i < bytes.length; i++) {
val = (char) (((bytes[i] & 0xf0) >> 4) & 0x0f);
temp[i * 2] = (char) (val > 9 ? val + 'A' - 10 : val + '0');
val = (char) (bytes[i] & 0x0f);
temp[i * 2 + 1] = (char) (val > 9 ? val + 'A' - 10 : val + '0');
}
return new String(temp);
}
//----------------------------------------------------------------- Private method start
/**
* 转换单个byte为BCD
* @param asc ACSII
* @return BCD
*/
private static byte ascToBcd(byte asc) {
byte bcd;
if ((asc >= '0') && (asc <= '9')) {
bcd = (byte) (asc - '0');
}else if ((asc >= 'A') && (asc <= 'F')) {
bcd = (byte) (asc - 'A' + 10);
}else if ((asc >= 'a') && (asc <= 'f')) {
bcd = (byte) (asc - 'a' + 10);
}else {
bcd = (byte) (asc - 48);
}
return bcd;
}
//----------------------------------------------------------------- Private method end
}
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