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/*
 * Licensed to the Apache Software Foundation (ASF) under one or more
 * contributor license agreements.  See the NOTICE file distributed with
 * this work for additional information regarding copyright ownership.
 * The ASF licenses this file to You under the Apache License, Version 2.0
 * (the "License"); you may not use this file except in compliance with
 * the License.  You may obtain a copy of the License at
 *
 *      http://www.apache.org/licenses/LICENSE-2.0
 *
 * Unless required by applicable law or agreed to in writing, software
 * distributed under the License is distributed on an "AS IS" BASIS,
 * WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
 * See the License for the specific language governing permissions and
 * limitations under the License.
 */
package org.apache.commons.math.util;

import org.apache.commons.math.ConvergenceException;
import org.apache.commons.math.MathException;
import org.apache.commons.math.MaxIterationsExceededException;
import org.apache.commons.math.exception.util.LocalizedFormats;

/**
 * Provides a generic means to evaluate continued fractions.  Subclasses simply
 * provided the a and b coefficients to evaluate the continued fraction.
 *
 * 

* References: *

*

* * @version $Revision: 990655 $ $Date: 2010-08-29 23:49:40 +0200 (dim. 29 août 2010) $ */ public abstract class ContinuedFraction { /** Maximum allowed numerical error. */ private static final double DEFAULT_EPSILON = 10e-9; /** * Default constructor. */ protected ContinuedFraction() { super(); } /** * Access the n-th a coefficient of the continued fraction. Since a can be * a function of the evaluation point, x, that is passed in as well. * @param n the coefficient index to retrieve. * @param x the evaluation point. * @return the n-th a coefficient. */ protected abstract double getA(int n, double x); /** * Access the n-th b coefficient of the continued fraction. Since b can be * a function of the evaluation point, x, that is passed in as well. * @param n the coefficient index to retrieve. * @param x the evaluation point. * @return the n-th b coefficient. */ protected abstract double getB(int n, double x); /** * Evaluates the continued fraction at the value x. * @param x the evaluation point. * @return the value of the continued fraction evaluated at x. * @throws MathException if the algorithm fails to converge. */ public double evaluate(double x) throws MathException { return evaluate(x, DEFAULT_EPSILON, Integer.MAX_VALUE); } /** * Evaluates the continued fraction at the value x. * @param x the evaluation point. * @param epsilon maximum error allowed. * @return the value of the continued fraction evaluated at x. * @throws MathException if the algorithm fails to converge. */ public double evaluate(double x, double epsilon) throws MathException { return evaluate(x, epsilon, Integer.MAX_VALUE); } /** * Evaluates the continued fraction at the value x. * @param x the evaluation point. * @param maxIterations maximum number of convergents * @return the value of the continued fraction evaluated at x. * @throws MathException if the algorithm fails to converge. */ public double evaluate(double x, int maxIterations) throws MathException { return evaluate(x, DEFAULT_EPSILON, maxIterations); } /** *

* Evaluates the continued fraction at the value x. *

* *

* The implementation of this method is based on equations 14-17 of: *

* The recurrence relationship defined in those equations can result in * very large intermediate results which can result in numerical overflow. * As a means to combat these overflow conditions, the intermediate results * are scaled whenever they threaten to become numerically unstable.

* * @param x the evaluation point. * @param epsilon maximum error allowed. * @param maxIterations maximum number of convergents * @return the value of the continued fraction evaluated at x. * @throws MathException if the algorithm fails to converge. */ public double evaluate(double x, double epsilon, int maxIterations) throws MathException { double p0 = 1.0; double p1 = getA(0, x); double q0 = 0.0; double q1 = 1.0; double c = p1 / q1; int n = 0; double relativeError = Double.MAX_VALUE; while (n < maxIterations && relativeError > epsilon) { ++n; double a = getA(n, x); double b = getB(n, x); double p2 = a * p1 + b * p0; double q2 = a * q1 + b * q0; boolean infinite = false; if (Double.isInfinite(p2) || Double.isInfinite(q2)) { /* * Need to scale. Try successive powers of the larger of a or b * up to 5th power. Throw ConvergenceException if one or both * of p2, q2 still overflow. */ double scaleFactor = 1d; double lastScaleFactor = 1d; final int maxPower = 5; final double scale = FastMath.max(a,b); if (scale <= 0) { // Can't scale throw new ConvergenceException( LocalizedFormats.CONTINUED_FRACTION_INFINITY_DIVERGENCE, x); } infinite = true; for (int i = 0; i < maxPower; i++) { lastScaleFactor = scaleFactor; scaleFactor *= scale; if (a != 0.0 && a > b) { p2 = p1 / lastScaleFactor + (b / scaleFactor * p0); q2 = q1 / lastScaleFactor + (b / scaleFactor * q0); } else if (b != 0) { p2 = (a / scaleFactor * p1) + p0 / lastScaleFactor; q2 = (a / scaleFactor * q1) + q0 / lastScaleFactor; } infinite = Double.isInfinite(p2) || Double.isInfinite(q2); if (!infinite) { break; } } } if (infinite) { // Scaling failed throw new ConvergenceException( LocalizedFormats.CONTINUED_FRACTION_INFINITY_DIVERGENCE, x); } double r = p2 / q2; if (Double.isNaN(r)) { throw new ConvergenceException( LocalizedFormats.CONTINUED_FRACTION_NAN_DIVERGENCE, x); } relativeError = FastMath.abs(r / c - 1.0); // prepare for next iteration c = p2 / q2; p0 = p1; p1 = p2; q0 = q1; q1 = q2; } if (n >= maxIterations) { throw new MaxIterationsExceededException(maxIterations, LocalizedFormats.NON_CONVERGENT_CONTINUED_FRACTION, x); } return c; } }




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