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/*******************************************************************************
 * Copyright (C) 2018 OTK Software
 * 
 * This program is free software: you can redistribute it and/or modify
 * it under the terms of the GNU General Public License as published by
 * the Free Software Foundation, either version 3 of the License, or
 * (at your option) any later version.
 * 
 * This program is distributed in the hope that it will be useful,
 * but WITHOUT ANY WARRANTY; without even the implied warranty of
 * MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.  See the
 * GNU General Public License for more details.
 * 
 * The GNU General Public License allows you also to freely redistribute 
 * the libraries under the same license, if you provide the terms of the 
 * GNU General Public License with them and add the following 
 * copyright notice at the appropriate place (with a link to 
 * http://javacollection.net/reflectionui/ web site when possible).
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package xy.reflect.ui.util;
// Copyright (c) 2003-2009, Jodd Team (jodd.org). All Rights Reserved.

/**
 * Checks whether a string matches a given wildcard pattern. Possible patterns
 * allow to match single characters ('?') or any count of characters ('*').
 * Wildcard characters can be escaped (by an '\').
 * 

* This method uses recursive matching, as in linux or windows. regexp works the * same. This method is very fast, comparing to similar implementations. */ public class Wildcard { /** * Checks whether a string matches a given wildcard pattern. * * @param string * input string * @param pattern * pattern to match * @return true if string matches the pattern, otherwise * false */ public static boolean match(String string, String pattern) { return match(string, pattern, 0, 0); } /** * Checks if two strings are equals or if they {@link #match(String, String)}. * Useful for cases when matching a lot of equal strings and speed is important. */ public static boolean equalsOrMatch(String string, String pattern) { if (string.equals(pattern) == true) { return true; } return match(string, pattern, 0, 0); } /** * Internal matching recursive function. */ private static boolean match(String string, String pattern, int stringStartNdx, int patternStartNdx) { int pNdx = patternStartNdx; int sNdx = stringStartNdx; int pLen = pattern.length(); if (pLen == 1) { if (pattern.charAt(0) == '*') { // speed-up return true; } } int sLen = string.length(); boolean nextIsNotWildcard = false; while (true) { // check if end of string and/or pattern occurred if ((sNdx >= sLen) == true) { // end of string still may have pending '*' in pattern while ((pNdx < pLen) && (pattern.charAt(pNdx) == '*')) { pNdx++; } return pNdx >= pLen; } if (pNdx >= pLen) { // end of pattern, but not end of the string return false; } char p = pattern.charAt(pNdx); // pattern char // perform logic if (nextIsNotWildcard == false) { if (p == '\\') { pNdx++; nextIsNotWildcard = true; continue; } if (p == '?') { sNdx++; pNdx++; continue; } if (p == '*') { char pnext = 0; // next pattern char if (pNdx + 1 < pLen) { pnext = pattern.charAt(pNdx + 1); } if (pnext == '*') { // double '*' have the same effect as one '*' pNdx++; continue; } int i; pNdx++; // find recursively if there is any substring from the end of the // line that matches the rest of the pattern !!! for (i = string.length(); i >= sNdx; i--) { if (match(string, pattern, i, pNdx) == true) { return true; } } return false; } } else { nextIsNotWildcard = false; } // check if pattern char and string char are equals if (p != string.charAt(sNdx)) { return false; } // everything matches for now, continue sNdx++; pNdx++; } } // ---------------------------------------------------------------- utilities /** * Matches string to at least one pattern. Returns index of matched pattern, or * -1 otherwise. * * @see #match(String, String) */ public static int matchOne(String src, String[] patterns) { for (int i = 0; i < patterns.length; i++) { if (match(src, patterns[i]) == true) { return i; } } return -1; } }





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