smile.math.distance.LeeDistance Maven / Gradle / Ivy
/*******************************************************************************
* Copyright (c) 2010-2020 Haifeng Li. All rights reserved.
*
* Smile is free software: you can redistribute it and/or modify
* it under the terms of the GNU Lesser General Public License as
* published by the Free Software Foundation, either version 3 of
* the License, or (at your option) any later version.
*
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* GNU Lesser General Public License for more details.
*
* You should have received a copy of the GNU Lesser General Public License
* along with Smile. If not, see .
******************************************************************************/
package smile.math.distance;
/**
* In coding theory, the Lee distance is a distance between two strings
* x1x2...xn
and
* y1y2...yn
* of equal length n over the q-ary alphabet {0, 1, ..., q-1}
* of size q ≥ 2
, defined as
*
*
* sum min(|xi-yi|, q-|xi-yi|)
*
* If q = 2
or q = 3
the Lee distance coincides with the Hamming distance.
*
* @author Haifeng Li
*/
public class LeeDistance implements Metric {
private static final long serialVersionUID = 1L;
private int q;
/**
* Constructor with a given size q of alphabet.
* @param q the size of q-ary alphabet.
*/
public LeeDistance(int q) {
if (q < 2) {
throw new IllegalArgumentException(String.format("The size of q-ary alphabet has to be larger than 1: q = %d", q));
}
this.q = q;
}
@Override
public String toString() {
return String.format("Lee Distance(q = %d)", q);
}
@Override
public double d(int[] x, int[] y) {
if (x.length != y.length) {
throw new IllegalArgumentException(String.format("Arrays have different length: x[%d], y[%d]", x.length, y.length));
}
int dist = 0;
for (int i = 0; i < x.length; i++) {
double d = Math.abs(x[i] - y[i]);
dist += Math.min(d, q-d);
}
return dist;
}
}