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104 LeetCode algorithm problem solutions
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// #Medium #Top_100_Liked_Questions #Top_Interview_Questions #String #Dynamic_Programming
// #Data_Structure_II_Day_9_String #Algorithm_II_Day_14_Dynamic_Programming
// #Dynamic_Programming_I_Day_17 #Udemy_Strings #Big_O_Time_O(n)_Space_O(n)
// #2024_09_28_Time_297_ms_(97.22%)_Space_146.7_MB_(92.59%)
class Solution {
String longestPalindrome(String s) {
List newStr = List.filled(s.length * 2 + 1, '#');
for (int i = 0; i < s.length; i++) {
newStr[2 * i + 1] = s[i];
newStr[2 * i + 2] = '#';
}
List dp = List.filled(newStr.length, 0);
int friendCenter = 0;
int friendRadius = 0;
int lpsCenter = 0;
int lpsRadius = 0;
for (int i = 0; i < newStr.length; i++) {
dp[i] = (friendCenter + friendRadius > i)
? (dp[friendCenter * 2 - i] < (friendCenter + friendRadius) - i
? dp[friendCenter * 2 - i]
: (friendCenter + friendRadius) - i)
: 1;
while (i + dp[i] < newStr.length &&
i - dp[i] >= 0 &&
newStr[i + dp[i]] == newStr[i - dp[i]]) {
dp[i]++;
}
if (friendCenter + friendRadius < i + dp[i]) {
friendCenter = i;
friendRadius = dp[i];
}
if (lpsRadius < dp[i]) {
lpsCenter = i;
lpsRadius = dp[i];
}
}
return s.substring(
(lpsCenter - lpsRadius + 1) ~/ 2, (lpsCenter + lpsRadius - 1) ~/ 2);
}
}
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