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104 LeetCode algorithm problem solutions
// #Medium #Top_Interview_Questions #Math #Udemy_Integers
// #2024_10_03_Time_347_ms_(96.43%)_Space_153.6_MB_(5.61%)
class Solution {
int reverse(int x) {
int number = x.abs();
int reverseNumber = 0;
final int maxValue = 0x7fffffff;
while (number != 0) {
reverseNumber = reverseNumber * 10 + number % 10;
number = number ~/ 10;
}
if (reverseNumber > maxValue) {
return 0;
}
return x > 0 ? reverseNumber : -reverseNumber;
}
}
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