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104 LeetCode algorithm problem solutions
package s0221_maximal_square
// #Medium #Top_100_Liked_Questions #Array #Dynamic_Programming #Matrix
// #Dynamic_Programming_I_Day_16 #Big_O_Time_O(m*n)_Space_O(m*n)
// #2024_03_22_Time_0_ms_(100.00%)_Space_7_MB_(29.80%)
func maximalSquare(matrix [][]byte) int {
m := len(matrix)
if m == 0 {
return 0
}
n := len(matrix[0])
if n == 0 {
return 0
}
dp := make([][]int, m+1)
for i := range dp {
dp[i] = make([]int, n+1)
}
max := 0
for i := 0; i < m; i++ {
for j := 0; j < n; j++ {
if matrix[i][j] == '1' {
// 1 + minimum from cell above, cell to the left, cell diagonal upper-left
next := 1 + min(dp[i][j], min(dp[i+1][j], dp[i][j+1]))
// keep track of the maximum value seen
if next > max {
max = next
}
dp[i+1][j+1] = next
}
}
}
return max * max
}
func min(a, b int) int {
if a < b {
return a
}
return b
}
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