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Java-based LeetCode algorithm problem solutions, regularly updated
2157\. Groups of Strings
Hard
You are given a **0-indexed** array of strings `words`. Each string consists of **lowercase English letters** only. No letter occurs more than once in any string of `words`.
Two strings `s1` and `s2` are said to be **connected** if the set of letters of `s2` can be obtained from the set of letters of `s1` by any **one** of the following operations:
* Adding exactly one letter to the set of the letters of `s1`.
* Deleting exactly one letter from the set of the letters of `s1`.
* Replacing exactly one letter from the set of the letters of `s1` with any letter, **including** itself.
The array `words` can be divided into one or more non-intersecting **groups**. A string belongs to a group if any **one** of the following is true:
* It is connected to **at least one** other string of the group.
* It is the **only** string present in the group.
Note that the strings in `words` should be grouped in such a manner that a string belonging to a group cannot be connected to a string present in any other group. It can be proved that such an arrangement is always unique.
Return _an array_ `ans` _of size_ `2` _where:_
* `ans[0]` _is the **maximum number** of groups_ `words` _can be divided into, and_
* `ans[1]` _is the **size of the largest** group_.
**Example 1:**
**Input:** words = ["a","b","ab","cde"]
**Output:** [2,3]
**Explanation:**
- words[0] can be used to obtain words[1] (by replacing 'a' with 'b'), and words[2] (by adding 'b'). So words[0] is connected to words[1] and words[2].
- words[1] can be used to obtain words[0] (by replacing 'b' with 'a'), and words[2] (by adding 'a'). So words[1] is connected to words[0] and words[2].
- words[2] can be used to obtain words[0] (by deleting 'b'), and words[1] (by deleting 'a'). So words[2] is connected to words[0] and words[1].
- words[3] is not connected to any string in words.
Thus, words can be divided into 2 groups ["a","b","ab"] and ["cde"]. The size of the largest group is 3.
**Example 2:**
**Input:** words = ["a","ab","abc"]
**Output:** [1,3]
**Explanation:**
- words[0] is connected to words[1].
- words[1] is connected to words[0] and words[2].
- words[2] is connected to words[1].
Since all strings are connected to each other, they should be grouped together.
Thus, the size of the largest group is 3.
**Constraints:**
* 1 <= words.length <= 2 * 104
* `1 <= words[i].length <= 26`
* `words[i]` consists of lowercase English letters only.
* No letter occurs more than once in `words[i]`.