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Java-based LeetCode algorithm problem solutions, regularly updated
# Write your MySQL query statement below
# #Medium #LeetCode_Curated_SQL_70 #Database #SQL_I_Day_4_Union_and_Select
# #2022_04_14_Time_347_ms_(95.17%)_Space_0B_(100.00%)
select id,case
when p_id is null then 'Root'
when id in (select p_id from tree) then 'Inner'
else 'Leaf'
end as type
from tree;
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