g1101_1200.s1116_print_zero_even_odd.ZeroEvenOdd Maven / Gradle / Ivy
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Java-based LeetCode algorithm problem solutions, regularly updated
package g1101_1200.s1116_print_zero_even_odd;
// #Medium #Concurrency #2023_06_01_Time_7_ms_(38.76%)_Space_42_MB_(38.97%)
import java.util.concurrent.Semaphore;
import java.util.function.IntConsumer;
@SuppressWarnings({"java:S2142", "java:S2583"})
public class ZeroEvenOdd {
private int n;
private final Semaphore zeroSemaphore = new Semaphore(1);
private final Semaphore oddSemaphore = new Semaphore(1);
private final Semaphore evenSemaphore = new Semaphore(1);
public ZeroEvenOdd(int n) {
this.n = n;
try {
oddSemaphore.acquire();
evenSemaphore.acquire();
} catch (InterruptedException ignored) {
// ignored
}
}
// printNumber.accept(x) outputs "x", where x is an integer.
public void zero(IntConsumer printNumber) throws InterruptedException {
for (int i = 1; i <= n; i++) {
zeroSemaphore.acquire();
printNumber.accept(0);
if (i % 2 == 0) {
oddSemaphore.release();
} else {
evenSemaphore.release();
}
}
oddSemaphore.release();
evenSemaphore.release();
}
public void odd(IntConsumer printNumber) throws InterruptedException {
for (int i = 1; i <= n; i += 2) {
evenSemaphore.acquire();
if (i > n) {
zeroSemaphore.release();
evenSemaphore.release();
break;
}
printNumber.accept(i);
zeroSemaphore.release();
}
}
public void even(IntConsumer printNumber) throws InterruptedException {
for (int i = 2; i <= n; i += 2) {
oddSemaphore.acquire();
if (i > n) {
zeroSemaphore.release();
oddSemaphore.release();
break;
}
printNumber.accept(i);
zeroSemaphore.release();
}
}
}