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Java-based LeetCode algorithm problem solutions, regularly updated

There is a newer version: 1.35

936\. Stamping The Sequence

Hard

You are given two strings `stamp` and `target`. Initially, there is a string `s` of length `target.length` with all `s[i] == '?'`.

In one turn, you can place `stamp` over `s` and replace every letter in the `s` with the corresponding letter from `stamp`.

*   For example, if `stamp = "abc"` and `target = "abcba"`, then `s` is `"?????"` initially. In one turn you can:

    *   place `stamp` at index `0` of `s` to obtain `"abc??"`,
    *   place `stamp` at index `1` of `s` to obtain `"?abc?"`, or
    *   place `stamp` at index `2` of `s` to obtain `"??abc"`.

    Note that `stamp` must be fully contained in the boundaries of `s` in order to stamp (i.e., you cannot place `stamp` at index `3` of `s`).

We want to convert `s` to `target` using **at most** `10 * target.length` turns.

Return _an array of the index of the left-most letter being stamped at each turn_. If we cannot obtain `target` from `s` within `10 * target.length` turns, return an empty array.

**Example 1:**

**Input:** stamp = "abc", target = "ababc"

**Output:** [0,2]

**Explanation:** Initially s = "?????". 
- Place stamp at index 0 to get "abc??". 
- Place stamp at index 2 to get "ababc". 
  
[1,0,2] would also be accepted as an answer, as well as some other answers.

**Example 2:**

**Input:** stamp = "abca", target = "aabcaca"

**Output:** [3,0,1]

**Explanation:** Initially s = "???????".
- Place stamp at index 3 to get "???abca". 
- Place stamp at index 0 to get "abcabca". 
- Place stamp at index 1 to get "aabcaca".

**Constraints:**

*   `1 <= stamp.length <= target.length <= 1000`
*   `stamp` and `target` consist of lowercase English letters.