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Java-based LeetCode algorithm problem solutions, regularly updated

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1179\. Reformat Department Table

Easy

SQL Schema

Table: `Department`

    +-------------+---------+
    | Column Name |  Type   |
    +-------------+---------+
    | id          | int     |
    | revenue     | int     |
    | month       | varchar |
    +-------------+---------+

(id, month) is the primary key of this table.

The table has information about the revenue of each department per month.

The month has values in ["Jan","Feb","Mar","Apr","May","Jun","Jul","Aug","Sep","Oct","Nov","Dec"].

Write an SQL query to reformat the table such that there is a department id column and a revenue column **for each month**.

Return the result table in **any order**.

The query result format is in the following example.

**Example 1:**

**Input:**

Department table:

    +------+---------+-------+
    | id   | revenue | month |
    +------+---------+-------+
    | 1    | 8000    | Jan   |
    | 2    | 9000    | Jan   |
    | 3    | 10000   | Feb   |
    | 1    | 7000    | Feb   |
    | 1    | 6000    | Mar   |
    +------+---------+-------+

**Output:**

    +------+-------------+-------------+-------------+-----+-------------+
    | id   | Jan_Revenue | Feb_Revenue | Mar_Revenue | ... | Dec_Revenue |
    +------+-------------+-------------+-------------+-----+-------------+
    | 1    | 8000        | 7000        | 6000        | ... | null        |
    | 2    | 9000        | null        | null        | ... | null        |
    | 3    | null        | 10000       | null        | ... | null        |
    +------+-------------+-------------+-------------+-----+-------------+

**Explanation:** The revenue from Apr to Dec is null.

Note that the result table has 13 columns (1 for the department id + 12 for the months).