All Downloads are FREE. Search and download functionalities are using the official Maven repository.

g1701_1800.s1774_closest_dessert_cost.readme.md Maven / Gradle / Ivy

There is a newer version: 1.35
Show newest version
1774\. Closest Dessert Cost

Medium

You would like to make dessert and are preparing to buy the ingredients. You have `n` ice cream base flavors and `m` types of toppings to choose from. You must follow these rules when making your dessert:

*   There must be **exactly one** ice cream base.
*   You can add **one or more** types of topping or have no toppings at all.
*   There are **at most two** of **each type** of topping.

You are given three inputs:

*   `baseCosts`, an integer array of length `n`, where each `baseCosts[i]` represents the price of the ith ice cream base flavor.
*   `toppingCosts`, an integer array of length `m`, where each `toppingCosts[i]` is the price of **one** of the ith topping.
*   `target`, an integer representing your target price for dessert.

You want to make a dessert with a total cost as close to `target` as possible.

Return _the closest possible cost of the dessert to_ `target`. If there are multiple, return _the **lower** one._

**Example 1:**

**Input:** baseCosts = [1,7], toppingCosts = [3,4], target = 10

**Output:** 10

**Explanation:** Consider the following combination (all 0-indexed):

- Choose base 1: cost 7

- Take 1 of topping 0: cost 1 x 3 = 3

- Take 0 of topping 1: cost 0 x 4 = 0

Total: 7 + 3 + 0 = 10. 

**Example 2:**

**Input:** baseCosts = [2,3], toppingCosts = [4,5,100], target = 18

**Output:** 17

**Explanation:** Consider the following combination (all 0-indexed): - Choose base 1: cost 3 - Take 1 of topping 0: cost 1 x 4 = 4 - Take 2 of topping 1: cost 2 x 5 = 10 - Take 0 of topping 2: cost 0 x 100 = 0 Total: 3 + 4 + 10 + 0 = 17. You cannot make a dessert with a total cost of 18. 

**Example 3:**

**Input:** baseCosts = [3,10], toppingCosts = [2,5], target = 9

**Output:** 8

**Explanation:** It is possible to make desserts with cost 8 and 10. Return 8 as it is the lower cost. 

**Constraints:**

*   `n == baseCosts.length`
*   `m == toppingCosts.length`
*   `1 <= n, m <= 10`
*   1 <= baseCosts[i], toppingCosts[i] <= 104
*   1 <= target <= 104




© 2015 - 2024 Weber Informatics LLC | Privacy Policy