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2578\. Split With Minimum Sum

Easy

Given a positive integer `num`, split it into two non-negative integers `num1` and `num2` such that:

*   The concatenation of `num1` and `num2` is a permutation of `num`.
    *   In other words, the sum of the number of occurrences of each digit in `num1` and `num2` is equal to the number of occurrences of that digit in `num`.
*   `num1` and `num2` can contain leading zeros.

Return _the **minimum** possible sum of_ `num1` _and_ `num2`.

**Notes:**

*   It is guaranteed that `num` does not contain any leading zeros.
*   The order of occurrence of the digits in `num1` and `num2` may differ from the order of occurrence of `num`.

**Example 1:**

**Input:** num = 4325

**Output:** 59

**Explanation:** We can split 4325 so that `num1` is 24 and num2 `is` 35, giving a sum of 59. We can prove that 59 is indeed the minimal possible sum.

**Example 2:**

**Input:** num = 687

**Output:** 75

**Explanation:** We can split 687 so that `num1` is 68 and `num2` is 7, which would give an optimal sum of 75.

**Constraints:**

*   10 <= num <= 109




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