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Java-based LeetCode algorithm problem solutions, regularly updated
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package g0001_0100.s0013_roman_to_integer;
// #Easy #Top_100_Liked_Questions #Top_Interview_Questions #String #Hash_Table #Math
// #2024_02_11_Time_2_ms_(100.00%)_Space_44.5_MB_(76.62%)
public class Solution {
public int romanToInt(String s) {
int x = 0;
char y;
for (int i = 0; i < s.length(); i++) {
y = s.charAt(i);
switch (y) {
case 'I':
x = getX(s, x, i, 1, 'V', 'X');
break;
case 'V':
x += 5;
break;
case 'X':
x = getX(s, x, i, 10, 'L', 'C');
break;
case 'L':
x += 50;
break;
case 'C':
x = getX(s, x, i, 100, 'D', 'M');
break;
case 'D':
x += 500;
break;
case 'M':
x += 1000;
break;
default:
break;
}
}
return x;
}
private int getX(String s, int x, int i, int i2, char v, char x2) {
if (i + 1 == s.length()) {
x += i2;
} else if (s.charAt(i + 1) == v) {
x -= i2;
} else if (s.charAt(i + 1) == x2) {
x -= i2;
} else {
x += i2;
}
return x;
}
}
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