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Java-based LeetCode algorithm problem solutions, regularly updated
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package g0001_0100.s0043_multiply_strings;
// #Medium #String #Math #Simulation #Data_Structure_II_Day_8_String #Programming_Skills_II_Day_4
// #Level_2_Day_2_String #2023_08_11_Time_1_ms_(100.00%)_Space_41.2_MB_(87.78%)
public class Solution {
private int[] getIntArray(String s) {
char[] chars = s.toCharArray();
int[] arr = new int[chars.length];
for (int i = 0; i < chars.length; i++) {
arr[i] = chars[i] - '0';
}
return arr;
}
private String convertToStr(int[] res, int i) {
char[] chars = new char[res.length - i];
int k = 0;
for (; i < res.length; i++) {
chars[k] = (char) (res[i] + '0');
k++;
}
return new String(chars);
}
public String multiply(String num1, String num2) {
int[] arr1 = getIntArray(num1);
int[] arr2 = getIntArray(num2);
int[] res = new int[arr1.length + arr2.length];
int index = arr1.length + arr2.length - 1;
for (int i = arr2.length - 1; i >= 0; i--) {
int k = index--;
for (int j = arr1.length - 1; j >= 0; j--) {
res[k] += arr2[i] * arr1[j];
k--;
}
}
index = arr1.length + arr2.length - 1;
int carry = 0;
for (int i = index; i >= 0; i--) {
int temp = res[i] + carry;
res[i] = temp % 10;
carry = temp / 10;
}
int i = 0;
while (i < res.length && res[i] == 0) {
i++;
}
if (i > index) {
return "0";
} else {
return convertToStr(res, i);
}
}
}
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