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Java-based LeetCode algorithm problem solutions, regularly updated
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50\. Pow(x, n)
Medium
Implement [pow(x, n)](http://www.cplusplus.com/reference/valarray/pow/), which calculates `x` raised to the power `n` (i.e., xn
).
**Example 1:**
**Input:** x = 2.00000, n = 10
**Output:** 1024.00000
**Example 2:**
**Input:** x = 2.10000, n = 3
**Output:** 9.26100
**Example 3:**
**Input:** x = 2.00000, n = -2
**Output:** 0.25000
**Explanation:** 2\-2 = 1/22 = 1/4 = 0.25
**Constraints:**
* `-100.0 < x < 100.0`
* -231 <= n <= 231-1
* -104 <= xn <= 104
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