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Java-based LeetCode algorithm problem solutions, regularly updated
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package g0001_0100.s0093_restore_ip_addresses;
// #Medium #String #Backtracking #2024_05_13_Time_1_ms_(99.27%)_Space_42_MB_(90.75%)
import java.util.ArrayList;
import java.util.List;
public class Solution {
private static final int SEG_COUNT = 4;
private List result = new ArrayList<>();
private int[] segments = new int[SEG_COUNT];
public List restoreIpAddresses(String s) {
dfs(s, 0, 0);
return result;
}
public void dfs(String s, int segId, int segStart) {
// find 4 segments and get to last index
if (segId == SEG_COUNT) {
if (segStart == s.length()) {
StringBuilder addr = new StringBuilder();
for (int i = 0; i < SEG_COUNT; i++) {
addr.append(segments[i]);
if (i != SEG_COUNT - 1) {
addr.append('.');
}
}
result.add(addr.toString());
}
return;
}
// last index and no 4 segments
if (segStart == s.length()) {
return;
}
// start with a zero
if (s.charAt(segStart) == '0') {
segments[segId] = 0;
dfs(s, segId + 1, segStart + 1);
return;
}
int addr = 0;
for (int index = segStart; index < s.length(); index++) {
addr = addr * 10 + s.charAt(index) - '0';
if (addr >= 0 && addr <= 255) {
segments[segId] = addr;
dfs(s, segId + 1, index + 1);
} else {
break;
}
}
}
}
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