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Java-based LeetCode algorithm problem solutions, regularly updated
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312\. Burst Balloons
Hard
You are given `n` balloons, indexed from `0` to `n - 1`. Each balloon is painted with a number on it represented by an array `nums`. You are asked to burst all the balloons.
If you burst the ith
balloon, you will get `nums[i - 1] * nums[i] * nums[i + 1]` coins. If `i - 1` or `i + 1` goes out of bounds of the array, then treat it as if there is a balloon with a `1` painted on it.
Return _the maximum coins you can collect by bursting the balloons wisely_.
**Example 1:**
**Input:** nums = [3,1,5,8]
**Output:** 167
**Explanation:**
nums = [3,1,5,8] --> [3,5,8] --> [3,8] --> [8] --> []
coins = 3*1*5 + 3*5*8 + 1*3*8 + 1*8*1 = 167
**Example 2:**
**Input:** nums = [1,5]
**Output:** 10
**Constraints:**
* `n == nums.length`
* `1 <= n <= 500`
* `0 <= nums[i] <= 100`
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