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package g0301_0400.s0316_remove_duplicate_letters;
// #Medium #String #Greedy #Stack #Monotonic_Stack
// #2022_07_08_Time_3_ms_(92.27%)_Space_42.6_MB_(75.22%)
public class Solution {
public String removeDuplicateLetters(String s) {
int[] charCount = new int[26];
boolean[] charAdded = new boolean[26];
// Build the char count array
for (char c : s.toCharArray()) {
charCount[c - 'a'] += 1;
}
StringBuilder sb = new StringBuilder();
// i = index of the input string
// j = index of the output stringBuilder
int j = 0;
for (int i = 0; i < s.length(); i++) {
char curr = s.charAt(i);
// If the curr char is NOT already added in the final string
if (!charAdded[curr - 'a']) {
// If the prev char in final string is lexicographically greater than curr char of
// input string
// And there are more characters in charCount array then we can remove this prev
// char from final string
// Do this check iteratively until all characters are removed from the final string
// or prev char < curr char
while (j > 0 && sb.charAt(j - 1) > curr && charCount[sb.charAt(j - 1) - 'a'] > 0) {
charAdded[sb.charAt(j - 1) - 'a'] = false;
sb.deleteCharAt(j - 1);
j--;
}
// Add the curr char in final string and mark that character as added in the string
sb.append(curr);
charAdded[curr - 'a'] = true;
j++;
}
// Reduce the count of the current character from the charCount array
charCount[curr - 'a'] -= 1;
}
return sb.toString();
}
}
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