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package g0401_0500.s0410_split_array_largest_sum;
// #Hard #Array #Dynamic_Programming #Greedy #Binary_Search
// #2022_07_16_Time_1_ms_(86.51%)_Space_41.4_MB_(68.72%)
public class Solution {
public int splitArray(int[] nums, int m) {
int maxVal = 0;
int minVal = nums[0];
for (int num : nums) {
maxVal += num;
minVal = Math.max(minVal, num);
}
while (minVal < maxVal) {
int midVal = minVal + (maxVal - minVal) / 2;
// if we can split, try to reduce the midVal so decrease maxVal
if (canSplit(midVal, nums, m)) {
maxVal = midVal;
} else {
// if we can't split, then try to increase midVal by increasing minVal
minVal = midVal + 1;
}
}
return minVal;
}
private boolean canSplit(int maxSubArrSum, int[] nums, int m) {
int currSum = 0;
int currSplits = 1;
for (int num : nums) {
currSum += num;
if (currSum > maxSubArrSum) {
currSum = num;
currSplits++;
// if maxSubArrSum was TOO high that we can split the array into more that 'm' parts
// then its not ideal
if (currSplits > m) {
return false;
}
}
}
return true;
}
}
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