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Java-based LeetCode algorithm problem solutions, regularly updated
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412\. Fizz Buzz
Easy
Given an integer `n`, return _a string array_ `answer` _(**1-indexed**) where_:
* `answer[i] == "FizzBuzz"` if `i` is divisible by `3` and `5`.
* `answer[i] == "Fizz"` if `i` is divisible by `3`.
* `answer[i] == "Buzz"` if `i` is divisible by `5`.
* `answer[i] == i` (as a string) if none of the above conditions are true.
**Example 1:**
**Input:** n = 3
**Output:** ["1","2","Fizz"]
**Example 2:**
**Input:** n = 5
**Output:** ["1","2","Fizz","4","Buzz"]
**Example 3:**
**Input:** n = 15
**Output:** ["1","2","Fizz","4","Buzz","Fizz","7","8","Fizz","Buzz","11","Fizz","13","14","FizzBuzz"]
**Constraints:**
* 1 <= n <= 104
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