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g0401_0500.s0419_battleships_in_a_board.readme.md Maven / Gradle / Ivy

419\. Battleships in a Board

Medium

Given an `m x n` matrix `board` where each cell is a battleship `'X'` or empty `'.'`, return _the number of the **battleships** on_ `board`.

**Battleships** can only be placed horizontally or vertically on `board`. In other words, they can only be made of the shape `1 x k` (`1` row, `k` columns) or `k x 1` (`k` rows, `1` column), where `k` can be of any size. At least one horizontal or vertical cell separates between two battleships (i.e., there are no adjacent battleships).

**Example 1:**

![](https://assets.leetcode.com/uploads/2021/04/10/battelship-grid.jpg)

**Input:** board = [["X",".",".","X"],[".",".",".","X"],[".",".",".","X"]]

**Output:** 2 

**Example 2:**

**Input:** board = [["."]]

**Output:** 0 

**Constraints:**

*   `m == board.length`
*   `n == board[i].length`
*   `1 <= m, n <= 200`
*   `board[i][j]` is either `'.'` or `'X'`.

**Follow up:** Could you do it in one-pass, using only `O(1)` extra memory and without modifying the values `board`?