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Java-based LeetCode algorithm problem solutions, regularly updated
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528\. Random Pick with Weight
Medium
You are given a **0-indexed** array of positive integers `w` where `w[i]` describes the **weight** of the ith
index.
You need to implement the function `pickIndex()`, which **randomly** picks an index in the range `[0, w.length - 1]` (**inclusive**) and returns it. The **probability** of picking an index `i` is `w[i] / sum(w)`.
* For example, if `w = [1, 3]`, the probability of picking index `0` is `1 / (1 + 3) = 0.25` (i.e., `25%`), and the probability of picking index `1` is `3 / (1 + 3) = 0.75` (i.e., `75%`).
**Example 1:**
**Input** ["Solution","pickIndex"] [[[1]],[]]
**Output:** [null,0]
**Explanation:**
Solution solution = new Solution([1]);
solution.pickIndex(); // return 0. The only option is to return 0 since there is only one element in w.
**Example 2:**
**Input**
["Solution","pickIndex","pickIndex","pickIndex","pickIndex","pickIndex"]
[[[1,3]],[],[],[],[],[]]
**Output:** [null,1,1,1,1,0]
**Explanation:**
Solution solution = new Solution([1, 3]);
solution.pickIndex(); // return 1. It is returning the second element (index = 1) that has a probability of 3/4.
solution.pickIndex(); // return 1
solution.pickIndex(); // return 1
solution.pickIndex(); // return 1
solution.pickIndex(); // return 0. It is returning the first element (index = 0) that has a probability of 1/4.
Since this is a randomization problem, multiple answers are allowed.
All of the following outputs can be considered correct:
[null,1,1,1,1,0]
[null,1,1,1,1,1]
[null,1,1,1,0,0]
[null,1,1,1,0,1]
[null,1,0,1,0,0]
......
and so on.
**Constraints:**
* 1 <= w.length <= 104
* 1 <= w[i] <= 105
* `pickIndex` will be called at most 104
times.
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